Answer:
C : 1.4*10^(-11) N.
Explanation:
q_1 = q_2 = 1.6 * 10^(-19)
R^2 = (1)^2 + (4)^2 = 1.7 * 10^(-17) m^2
The coulomb's law is as follows:
F_e = k*q_1*q_2 / R^2
F_e = k*q^2 / R^2
F_e = (9.0*10^9) * (1.6 * 10^(-19))^2 / 1.7 * 10^(-17)
F_e = 1.35 * 10^(-11) N
Hence, answer closes to obtained is option C : 1.4*10^(-11) N.
<span>The answer is in m/s</span>
Answer:
It captures images but does not preserve them.
All four values are in 3 sig. fig.
<h3>Explanation</h3>
(a)
.
(b)
Sum of the final charge on the two capacitors should be the same as the sum of the initial charge. Voltage of the two capacitors should be the same. That is:
;
;
.
(c)
.
.
(d)
Initial energy of the system, which is the same as the initial energy in the
capacitor:
.
Change in energy:
.
Real images can be either upright or inverted. Real images can be magnified in size, reduced in size or the same size as the object. Real images can be formed by concave, convex and plane mirrors. Real images are not virtual; thus you could never see them when sighting in a mirror.