All categories

3 years ago

What object in the universe that reflect light from stars

Physics

2 answers:

alexdok [17]3 years ago

7 0

The moon reflects light from stars and then the light is moon light.

SSSSS [86.1K]3 years ago

3 0

Every object that is not a star is visible only when a star's light shines
on it. Then, some of the star's light may be reflected from the object,
to our eyes.

Objects that do not generate light, and are visible only when illuminated
by a star's light, include planets, moons, comets, asteroids, meteoroids,
and artificial satellites without batteries and headlights.

You might be interested in

Water is flowing in a pipe with a circular cross section but with varying cross-sectional area, and at all points the water comp

slamgirl [31]

(a) 5.66 m/s

The flow rate of the water in the pipe is given by

$Q=Av$

where

Q is the flow rate

A is the cross-sectional area of the pipe

v is the speed of the water

Here we have

$Q=1.20 m^3/s$

the radius of the pipe is

r = 0.260 m

So the cross-sectional area is

$A=\pi r^2 = \pi (0.260 m)^2=0.212 m^2$

So we can re-arrange the equation to find the speed of the water:

$v=\frac{Q}{A}=\frac{1.20 m^3/s}{0.212 m^2}=5.66 m/s$

(b) 0.326 m

The flow rate along the pipe is conserved, so we can write:

$Q_1 = Q_2\\A_1 v_1 = A_2 v_2$

where we have

$A_1 = 0.212 m^2\\v_1 = 5.66 m/s\\v_2 = 3.60 m/s$

and where $A_2$ is the cross-sectional area of the pipe at the second point.

Solving for A2,

$A_2 = \frac{A_1 v_1}{v_2}=\frac{(0.212 m^2)(5.66 m/s)}{3.60 m/s}=0.333 m^2$

And finally we can find the radius of the pipe at that point:

$A_2 = \pi r_2^2\\r_2 = \sqrt{\frac{A_2}{\pi}}=\sqrt{\frac{0.333 m^2}{\pi}}=0.326 m$

6 0

3 years ago

If an astronaut has a mass of 80kg on earth, what is their mass on the moon?

stealth61 [152]

Answer:

130 N basically

Explanation:

6 0

2 years ago

Which of the following has a negative acceleration?

Volgvan

Answer:

B. A car sits at rest at a stop sign.

6 0

3 years ago

In a video game, a flying coconut moves at a constant velocity of 20 meters/second. The coconut hits an obstacle and moves in th

qwelly [4]

Change in velocity = Final velocity - Initial velocity

Initial velocity = 20 m/s
Final velocity = 10 m/s

Change in velocity = 10 - 20 = -10m/s

Correct option B

Hope This Helps You!

4 0

3 years ago

Which of the following describes the relationship between the weight of fluid displaced by an object and the buoyant force exert

PilotLPTM [1.2K]

Answer:

Archimedes' principle

Explanation:

apex

6 0

3 years ago