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just olya [345]
4 years ago
14

Problem PageQuestion Suppose a rhodium atom in the oxidation state formed a complex with one iodide anion and five ammonia molec

ules. Write the chemical formula of this complex.

Chemistry
2 answers:
Angelina_Jolie [31]4 years ago
5 0

Answer:

It forms an octahedral complex

Rh[NH3]5I

Explanation:

Or see structure attached below

Kamila [148]4 years ago
3 0

Answer:

[ Rhl(NH₃)₅]²⁺

Explanation:

Symbol of Rhodium atom = Rh

charge of Rhodium in complex = +3

charge on Iodine in complex = -1

Charge on NH₃= 0 (neutral)

Therefore, the total charge on the complex is given as follows;

Charge on complex= +3-1 + 0

                                        = +2

Therefore, the required formula of the complex = [ Rhl(NH₃)₅]²⁺

[Note: Inside the co-ordination complex,metal is written first and followed by negative and neutral ligands respectively and charge on complex is written on the right top of the complex. therefore, the chemical formular of the given complex is given as follows; [ Rhl(NH₃)₅]²⁺

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Explanation:

Here is the answer hope you do well

4 0
3 years ago
23.495 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 72.311 g of wate
Otrada [13]

Answer:

1.86% NH₃

Explanation:

The reaction that takes place is:

  • HCl(aq) + NH₃(aq) → NH₄Cl(aq)

We <u>calculate the moles of HCl that reacted</u>, using the volume used and the concentration:

  • 32.27 mL ⇒ 32.27/1000 = 0.03227 L
  • 0.1080 M * 0.03227 L = 3.4852x10⁻³ mol HCl

The moles of HCl are equal to the moles of NH₃, so now we <u>calculate the mass of NH₃ that was titrated</u>, using its molecular weight:

  • 3.4852x10⁻³ mol NH₃ * 17 g/mol = 0.0592 g NH₃

The weight percent NH₃ in the aliquot (and thus in the diluted sample) is:

  • 0.0592 / 12.949 * 100% = 0.4575%

Now we <u>calculate the total mass of NH₃ in the diluted sample</u>:

Diluted sample total mass = Aqueous waste Mass + Water mass = 23.495 + 72.311 = 95.806 g

  • 0.4575% * 95.806 g = 0.4383 g NH₃

Finally we calculate the weight percent NH₃ in the original sample of aqueous waste:

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6 0
3 years ago
Why is gold found in the pure state in nature?
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5 0
3 years ago
A container is filled with a gas. The container has a wall controlled by a moveable piston. The
ioda

Answer:

The new volume will be 3.67 L.

Explanation:

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them fewer times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:

"The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

P*V=k

Now it is possible to assume that you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:

P1 * V1 = P2 * V2

In this case:

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  • P2= 2.34 atm
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Replacing:

1.85 atm* 4.64 L= 2.34 atm* V2

Solving:

V2= \frac{1.85 atm* 4.64 L}{2.34 atm}

V2= 3.67 L

<u><em>The new volume will be 3.67 L.</em></u>

6 0
3 years ago
Argon-39 has a half-life of 269 years. How long will it take for 52.5 g of a 60.0 g sample to decay to its daughter isotope?
777dan777 [17]
For 60.0 g sample, if it remains 60-52.5=7.5 g, it will go through 60->30->15->7.5, 3 half-life. So the time being taken is 269*3=807 years.
3 0
3 years ago
Read 2 more answers
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