Find the value of each variable. For the circle, the dot represents the center.
1 answer:
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Answer:
<h2>0.00390625 /Step-by-step explanation:
so you are saying do:
which is 16 /4096
16/4096=0.00390625
<u>another way you can do this is</u>
just subtract the powers
2-6=-4
so the answer is
Answer:
The probability that you will get the job If you apply for a job with Globo Corp=0.36
Step-by-step explanation:
We are given that
If you apply for a job with Globo Corp, then the probability of getting interview P(A)=75%=0.75
If you get an interview, then the probability of getting job=P(B)=48%=0.48
We have to find the probability that you will get the job If you apply for a job with Globo Corp.
If you apply for a job with Globo Corp, the probability of getting job=
If you apply for a job with Globo Corp, the probability of getting job=
If you apply for a job with Globo Corp, the probability of getting job=0.36
Hence, the probability that you will get the job If you apply for a job with Globo Corp=0.36
a. The inverse image of f(x) is f⁻¹(x) = ∛(x/3)
b. The inverse image of g(x) is
c. The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9
<h3 /><h3>The domain of T</h3>Since T = {x ∈ R : 0 ≤ [x^2 − 25} ⇒ x² - 25 ≥ 0
⇒ x² ≥ 25
⇒ x ≥ ±5
⇒ -5 ≤ x ≤ 5.
<h3>Inverse image of f(x)</h3>
The inverse image of f(x) is f⁻¹(x) = ∛(x/3)
f : R → R defined by f(x) = 3x³
Let f(x) = y.
So, y = 3x³
Dividing through by 3, we have
y/3 = x³
Taking cube root of both sides, we have
x = ∛(y/3)
Replacing y with x we have
y = ∛(x/3)
Replacing y with f⁻¹(x), we have
So, the inverse image of f(x) is f⁻¹(x) = ∛(x/3)
<h3>Inverse image of g(x)</h3>
The inverse image of g(x) is
g : R+ → R defined by g(x) = ln(x).
Let g(x) = y
y = ln(x)
Taking exponents of both sides, we have
Replacing x with y, we have
Replacing y with g⁻¹(x), we have
So, the inverse image of g(x) is
The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9
h : R → R defined by h(x) = x − 9
Let y = h(x)
y = x - 9
Adding 9 to both sides, we have
y + 9 = x
Replacing x with y, we have
x + 9 = y
Replacing y with h⁻¹(x), we have
So, the inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9
Learn more about inverse image of a function here: