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4 years ago

13

Consider only the first major feature, which concerns observed patterns of motion in the solar system. Scientifically, which of

the following possible conclusions is justified from the patterns of motion alone?

1 answer:

anzhelika [568]4 years ago

7 0

Answer:

All the planets have nearly circular orbit except the Pluto

Explanation:

Planets closer to the Sun move around their orbits at a very high speed than planets farther from the Sun.

All the planets except Pluto, orbit the Sun in nearly the same plane.

All the planets have nearly circular orbits except Pluto because of it's distance from the sun which is over 5,000,000,000km

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If you were on the moon, and you were trying to move a 20-lb bowling ball and a 3-foot cube of Styrofoam, which item would take

laila [671]

I think it is C since the mass will stay the same except not the gravity

5 0

4 years ago

Read 2 more answers

Thermopane window is constructed, using two layers of glass 4.0 mm thick, separated by an air space of 5.0 mm.

Bond [772]

To solve this problem it is necessary to apply the concepts related to rate of thermal conduction

$\frac{Q}{t} = \frac{kA\Delta T}{d}$

The letter Q represents the amount of heat transferred in a time t, k is the thermal conductivity constant for the material, A is the cross sectional area of the material transferring heat, $\Delta T$ , T is the difference in temperature between one side of the material and the other, and d is the thickness of the material.

The change made between glass and air would be determined by:

$(\frac{Q}{t})_{glass} = (\frac{Q}{t})_{air}$

$k_{glass}(\frac{A}{L})_{glass} \Delta T_{glass} = k_{air}(A/L)_{air} \Delta T_{air}$

$\Delta T_{air} = (\frac{k_{glass}}{k_{air}})(\frac{L_{air}}{L_{glass}}) \Delta T_{glass}$

$\Delta T_{air} = (\frac{0.84}{0.0234})(\frac{5}{4}) \Delta T_{glass}$

$\Delta T_{air} = 44.9 \Delta T_{glass}$

There are two layers of Glass and one layer of Air so the total temperature would be given as,

$\Delta T = \Delta T_{glass} +\Delta T_{air} +\Delta T_{glass}$

$\Delta T = 2\Delta T_{glass} +\Delta T_{air}$

$20\°C = 46.9\Delta T_{glass}$

$\Delta T_{glass} = 0.426\°C$

Finally the rate of heat flow through this windows is given as,

$\Delta {Q}{t} = k_{glass}\frac{A}{L_{glass}}\Delta T_{glass}$

$\Delta {Q}{t} = 0.84*24*10 -3*0.426$

$\Delta {Q}{t} = 179W$

Therefore the correct answer is D. 180W.

3 0

3 years ago

The Nardo ring is a circular test track for cars. It has a circumference of 12.5 km. Cars travel around the track at a constant

KIM [24]

Answer: 50 km, 0, 27.78 m/s

Explanation:

Given

Circumference of the track is $12.5\ km$

Speed of car is $100\ km/h$

Car drives for $30\ \text{minute}\ or\ 0.5\ hr$

(a)Distance traveled is

$\Rightarrow D=100\times 0.5\\\Rightarrow D=50\ km$

(b)displacement of the car

It can be observed that 12.5 is a multiple of 50, that is, 50 km can be interpreted as 4 complete rounds of the track.

Therefore, the displacement of the car is zero.

(c)To convert kmph to m/s, multiply the entity by $\frac{5}{18}$

$\Rightarrow 100\times \dfrac{5}{18}\\\\\Rightarrow 27.78\ m/s$

5 0

3 years ago

A 1.0-m-tall vertical tube is filled with 20°C water. A tuning fork vibrating at 580 Hz is held just over the top of the tube as

Mademuasel [1]

Answer:

water heights of the tube are 0.851 m , 0.553 m, 0.255 m

Explanation:

given data

frequency = 580 Hz

temperature = 20°C

tube = 1 m

to find out

water heights of the tube

solution

we will apply here formula for length that is

length L = v ( 2n -1 ) / 4f

here v is velocity o sound that is 343.2 m/s

so for n = 1

L = 343.2 ( 2(1) -1 ) / 4(580) = 0.147931 m

for n = 2

L = 343.2 ( 2(2) -1 ) / 4(580) = 0.443793 m

for n = 3

L = 343.2 ( 2(3) -1 ) / 4(580) = 0.739655 m

for n = 4

L = 343.2 ( 2(4) -1 ) / 4(580) = 1.035517 m is greater than 1

and so here height is measured less than 1 m

so water heights of the tube are 1 m - 0.147931 m , 1 m - 0.443793 m, 1 m - 0.739655 m

so water heights of the tube are 0.851 m , 0.553 m, 0.255 m

3 0

3 years ago

Help asap!! The resultant force on the box is

rodikova [14]

The resultant force on the box is C) 10 Newtons to the left.

Explanation:

The figure of the problem is attached.

We see that there are two forces acting on the box along the horizontal direction:

- A force of 10 N acting to the right

- A force of 20 N acting to the left

By taking "to the right" as positive direction, we can rewrite the two forces as follows:

$F_1 = +10 N\\F_2 = -20 N$

Where the second force is negative since it acts to the left.

Since the two forces are in line, we can find their resultant simply by calculating their algebraic sum. By doing so, we find:

$F=F_1 + F_2 = +10 + (-20) = -10 N$

And the negative sign tells us that the direction is to the left.

Therefore, the correct answer is

C) 10 Newtons to the left.

Learn more about forces here:

brainly.com/question/12978926

#LearnwithBrainly

5 0

3 years ago