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CaHeK987 [17]
4 years ago
11

For this problem, imagine that you are on a ship that is oscillating up and down on a rough sea. Assume for simplicity that this

is simple harmonic motion (in the vertical direction) with amplitude 5 cm and frequency 2 Hz. There is a box on the floor with mass m = 1 kg.
(a) Assuming the box remains in contact with the floor throughout, find the maximum and minimum values of the normal force exerted on it by the floor over an oscillation cycle.
(b) How large would the amplitude of the oscillations have to become for the box to lose contact with the floor, assuming the frequency remains constant? (Hint: what is the value of the normal force at the moment the box loses contact with the floor?)
Physics
1 answer:
ikadub [295]4 years ago
7 0

Answer:

no idea

Explanation:

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a 20 kg projectile is launched from a cannon. a. if the projectile leaves the cannon with a velocity of 54 m/s, what is the work
Artyom0805 [142]

Answer:

KE = 1/2 M v^2       kinetic energy of projectile

KE = 1/2 * 20 * (54 m/s)^2 = work done on projectile

W = 10 * 54^2 = work done on projectile

W = 29,160 J

7 0
2 years ago
Self-registering thermometers are used for:
Angelina_Jolie [31]

Self-registering thermometers are used for temperature or depth profile. It registers the maximum and minimum temperature of the substance occurring in the interval of time between two consecutive settings of the instrument.

5 0
3 years ago
Which term is defined as an elongated area of low pressure?
fenix001 [56]

Answer:

A trough

Explanation:

A trough is an elongated area of relatively low pressure extending from the center of a region of low pressure.

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6 0
3 years ago
A car owner forgets to turn off the headlights of his car while it is parked in his garage. If the 12.0-V battery in his car is
luda_lava [24]

Answer:

It will take time=7.963 hours to completely discharge  

Explanation:

The energy available in the battery is:

Energy stored=Power×Time

Energy stored=(ΔV)I×t  

Energy stored=(12.0V×43.0A.h)

Energy stored=516 W.h

The two headlights together consume a total power of:

P=2*32.4W\\P=64.8W

So the time required to completely discharge is:

time=\frac{Energy.stored}{P}\\ time=\frac{516 W.h}{64.8W}\\ time=7.963hours

It will take time=7.963 hours to completely discharge  

3 0
4 years ago
Read 2 more answers
What affects the vertical velocity of a projectile over time?<br>---​
kobusy [5.1K]
The vertical velocity is affected by the acceleration of gravity (ignoring the effects of air resistance usually)
6 0
3 years ago
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