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Talja [164]
4 years ago
13

Consider a 1.72-m-tall man standing vertically in water and completely submerged in a pool. Determine the difference between the

pressures acting at the head and at the toes of this man, in kPa. The pressure difference acting between the head and toes of the man is kPa.
Physics
1 answer:
bazaltina [42]4 years ago
5 0

Answer:

Pressure difference between head and toes = 16872.2 Pa

Explanation:

The pressure difference between the head and toes of the man will be equal to the water pressure exerted at his toes. This can be found as follows:

Water pressure = (density of water) * (gravity) * (height of water)

Density of water = 1000 kg/m^3

Gravity = 9.81 m/s^2

Height of water = height of man = 1.72 m

Water pressure = 1000 * 9.81 * 1.72

Water pressure = 16872.2 Pa  

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marshall27 [118]

Answer:

A. The brakes used a coil system to convert the kinetic energy into potential energy stored in the brakes

Explanation:

Based on the law of conservation of energy, the brakes used a coil system to convert the kinetic energy into potential energy stored in the brakes.

The law of conservation of energy states that energy is neither created nor destroyed in a system but it is transformed from one form to another.

As the airplane slows down, the kinetic energy which is presented in the motion of the plane is gradually converted to potential energy.

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8 0
3 years ago
Is a pair of scissorrs a lever and wedge?
Ivahew [28]

Answer:

Wedge

Explanation:

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7 0
2 years ago
A box is at rest on a ramp at an incline of 22°. The normal force on the box is 538 N.
fomenos

Answer: 580 N

Refer to attached figure.

The angle of inclination is 22 degrees

weight (gravitational force) acts downwards.

Normal force is a contact force which acts perpendicular to the point of contact.

The horizontal component (mg cos 22 ) balances the normal force and the vertical component balances the frictional force.

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The normal force N= mg cos 22

\Rightarrow mg =\frac{N}{cos22}=\frac{538 N}{0.927}=580 N





8 0
3 years ago
Read 2 more answers
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 54.0 cm. The explorer finds that
Natasha2012 [34]

Answer:

g = 11.2 m/s²

Explanation:

First, we will calculate the time period of the pendulum:

T = \frac{t}{n}

where,

T = Time period = ?

t = time taken = 135 s

n = no. of swings in given time = 98

Therefore,

T = \frac{135\ s}{98}

T = 1.38 s

Now, we utilize the second formula for the time period of the simple pendulum, given as follows:

T = 2\pi \sqrt{\frac{l}{g}}

where,

l = length of pendulum = 54 cm = 0.54 m

g = acceleration due to gravity on the planet = ?

Therefore,

(1.38\ s)^2 = 4\pi^2(\frac{0.54\ m}{g} )\\\\g = \frac{4\pi^2(0.54\ m)}{(1.38\ s)^2}

<u>g = 11.2 m/s²</u>

3 0
3 years ago
Which one of the following is NOT a simple machine?
ivann1987 [24]
It is hammer because hammers are not examples of a simple machine
6 0
3 years ago
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