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Deffense [45]
3 years ago
13

A proton traveling with speed 2 × 105 m/s in the -y direction passes through a region in which there is a uniform magnetic field

of magnitude 0.6 T in the -z direction. You want to keep the proton traveling in a straight line at constant speed. To do this, you can turn on an apparatus that can create a uniform electric field throughout the region. What electric field should you apply?
Physics
1 answer:
stepladder [879]3 years ago
5 0

Answer:

\vec{E} =  1.2\times 10^5(-i)

Explanation:

Given that

Speed ,v= 2 x 10⁵ m/s ( - y direction)

B= 0.6 T (- z direction)

The resultant force on the proton given as

\vec{F}=q.\vec{E}+ q.(\vec{v}\times \vec{B})

F= m a

For uniform motion acceleration should be zero.

F = 0

0=q.\vec{E}+ q.(\vec{v}\times \vec{B})

0=\vec{E}+ (\vec{v}\times \vec{B})

0=\vec{E}+2\times 10^5(-j) \times 0.6(-k)

\vec{E} =- 2\times 10^5(-j) \times 0.6(-k)

\vec{E} =-1.2\times 10^5(i)

\vec{E} = 1.2\times 10^5(-i)

Electric filed should be apply in the negative x direction.

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ale4655 [162]

Answer:

140265.8 C = 1.403 × 10⁵ C

Explanation:

The battery's electric potential energy is used to account for the kinetic and potential work done in moving the car up this hill.

Potential work required to move the 757 kg car up a vertical height of 195 m = mgh

P.E = 757 × 9.8 × 195 = 1446627 J

Kinetic work done = (1/2)(m)(v²)

K.E = (1/2)(757)(25²) = 236562.5 J

Total work done in moving the car up that height = 1446627 + 236562.5 = 1683189.5 J

And this would be equal to the potential of the battery.

For the battery, potential difference = (electric potential energy)/(charges moved)

ΔV = ΔU/q

q = ΔU/ΔV

ΔU = 1683189.5 J

ΔV = 12.0 V

q = 1683189.5/12 = 140265.8 C

7 0
3 years ago
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Can some one help me with this question its hard :( down below ill give brainliest
tensa zangetsu [6.8K]
I’m pretty sure it’s c sorry if I’m wrong
3 0
3 years ago
Match the following:
Art [367]

Answer:

1) Tailored software  Library management system

2) Utility software Scan viruses

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4) Packaged software set of programs Microsoft office

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2) A utility software is a computer maintenance and analysis software used to enable proper functioning of the computer by performing restorative and maintenance tasks

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-- 45 minutes = (45 x 60) = 2,700 seconds

-- Power = (work) / (time) = (2,000,000 j) / (2,700 s) = <u>740.74 watts</u>

Interestingly, that's almost exactly 1 horsepower.  (0.99295... of 746 watts)
8 0
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