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aksik [14]
3 years ago
11

To use an automated teller machine (ATM), a customer must enter his or her four-digit Personal Identification Number (PIN). How

many different PINs are possible?
Computers and Technology
1 answer:
schepotkina [342]3 years ago
6 0

Answer:

10000 possible PINs.

Explanation:

Considering the fact that only numbers are permitted (0 - 9) which gives 10 characters and also that the digits can be repeated, the total number of possible PINs that are possible is 10 x 10 x 10 x 10 = 10000

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You can use automatic link-checking software to identify invalid hyperlinks. if you find invalid links, what should you do next?
Solnce55 [7]
Correct the href value of the appropriate anchor.
7 0
2 years ago
John is analyzing strange behavior on computers in his network. He believes there is malware on the machines. The symptoms inclu
enot [183]

Answer:

Boot Sector Virus

Explanation:

A malicious software or malware is an executable line of code, programmed by a cybercriminal for ill intentions. There are many types of malware namely; viruses, rootkit, keylogger, trojan horse etc.

A boot sector virus is a kind of malware that runs before the operating system, affecting the boot sector of the hard disk, so even when a linux live cd is running as the operating system, the virus is still active.

5 0
3 years ago
Determine whether or not the following pairs of predicates are unifiable. If they are, give the most-general unifier and show th
Evgen [1.6K]

Answer:

a) P(B,A,B), P(x,y,z)

=> P(B,A,B) , P(B,A,B}  

Hence, most general unifier = {x/B , y/A , z/B }.

b. P(x,x), Q(A,A)  

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q.

c. Older(Father(y),y), Older(Father(x),John)

Thus , mgu ={ y/x , x/John }.

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))  

This is not unifiable as x cannot be bound for both A and B.

e) P(f(x), x, g(x)), P(f(y), A, z)    

=> P(f(A), A, g(A)), P(f(A), A, g(A))  

Thus , mgu = {x/y, z/y , y/A }.

Explanation:  

Unification: Any substitution that makes two expressions equal is called a unifier.  

a) P(B,A,B), P(x,y,z)  

Use { x/B}  

=> P(B,A,B) , P(B,y,z)  

Now use {y/A}  

=> P(B,A,B) , P(B,A,z)  

Now, use {z/B}  

=> P(B,A,B) , P(B,A,B}  

Hence, most general unifier = {x/B , y/A , z/B }  

b. P(x,x), Q(A,A)  

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q  

c. Older(Father(y),y), Older(Father(x),John)  

Use {y/x}  

=> Older(Father(x),x), Older(Father(x),John)  

Now use { x/John }  

=> Older(Father(John), John), Older(Father(John), John)  

Thus , mgu ={ y/x , x/John }  

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))  

Use { y/x }  

=> Q(G(x,z),G(z,x)), Q(G(x,x),G(A,B))

Use {z/x}  

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))  

This is not unifiable as x cannot be bound for both A and B  

e) P(f(x), x, g(x)), P(f(y), A, z)  

Use {x/y}  

=> P(f(y), y, g(y)), P(f(y), A, z)  

Now use {z/g(y)}  

P(f(y), y, g(y)), P(f(y), A, g(y))  

Now use {y/A}  

=> P(f(A), A, g(A)), P(f(A), A, g(A))  

Thus , mgu = {x/y, z/y , y/A }.

7 0
3 years ago
They will wash the car change into tag question​
valentina_108 [34]

Answer:

They will wash the car, won't they?

Explanation:

A tag question usually comes after an independent clause. The tag question is most times attached with the intent of affirming the statement made in the independent clause. Our independent clause in the answer above is; "They will wash the car". The tag question, "Won't they?" is meant to affirm that statement.

Another example is, "They are going to school, aren't they?" In this example also, the independent clause makes a sentence that is to be confirmed by the tag question.

8 0
2 years ago
Write a recursive method called repeat that accepts a string s and an integer n as parameters and that returns s concatenated to
svp [43]

Answer:

public static String repeat(String text, int repeatCount) {

   if(repeatCount < 0) {

       throw new IllegalArgumentException("repeat count should be either 0 or a positive value");

   }

   if(repeatCount == 0) {

       return "";

   } else {

       return text + repeat(text, repeatCount-1);

   }

}

Explanation:

Here repeatCount is an int value.

at first we will check if repeatCount is non negative number and if it is code will throw exception.

If the value is 0 then we will return ""

If the value is >0 then recursive function is called again untill the repeatCount value is 0.

6 0
3 years ago
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