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mezya [45]
3 years ago
11

Solve for b. b + (-42) = -86

Mathematics
1 answer:
blsea [12.9K]3 years ago
3 0

Answer:

100:7$+3733-5

Step-by-step explanation:

beacuse Yan ang answer

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The length of a rectangle is 5 in longer than its width.
NeTakaya

Answer:

Length = 21

Width = 16

Step-by-step explanation:

We know that the formula for perimeter is:

P=2W+2L

And we also know that:

L=W+5

So then we put all that we know in the formula:

74=2W+2(W+5)

Now we expand the brackets and do some algebra:

74=4W+10 (-10)

64=4W (÷4)

16=W

Now that we know the width we can pop that into the length equation:

L=16+5

L=21

5 0
3 years ago
Subtract 715 from the sum of 810 and 189
hodyreva [135]
810+189-715= 284. the answer is 284
3 0
3 years ago
Read 2 more answers
a rectangular pyramid has a volume of 190 cubic centimeters. Find two possible sets of measurements for the base area and height
DerKrebs [107]
<h3>One possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively</h3><h3>Other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively</h3>

<em><u>Solution:</u></em>

<em><u>The volume of rectangular pyramid is given as:</u></em>

Volume = \frac{1}{3} \times base\ area \times height

Given that,

<em><u>Rectangular pyramid has a volume of 190 cubic centimeters</u></em>

<em><u></u></em>190= \frac{1}{3} \times base\ area \times height<em><u></u></em>

<em><u>Substitute, base area = 570 and height = 1</u></em>

Then we get,

190 = \frac{1}{3} \times 570 \times 1\\\\190 = 190

Thus one possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively

<em><u>Substitute, base area = 285 and height = 2</u></em>

190 = \frac{1}{3} \times 285 \times 2\\\\190 = \frac{1}{3} \times 570\\\\190 = 190

Thus other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively

6 0
3 years ago
Identify a pair of perpendicular lines in the given figure.
Georgia [21]
S and t most likely
8 0
3 years ago
Solve ABCD. Round the answers to the nearest hundredth, if necessary.
VashaNatasha [74]

                     .......................................................................

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2 years ago
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