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ANEK [815]
3 years ago
13

Plz help 15 points to best answer. A ladder leans against a building, making a 70 degree angle of elevation with the ground. The

top of the ladder reaches a point on the building that is 39 feet above the ground. To the nearest tenth of a foot, what is the distance between the base of the building and the base of the ladder?
13.3
14.2
36.6
41.5
Mathematics
1 answer:
NeTakaya3 years ago
3 0
For this case, we can model the problem as a rectangle triangle.
 We know the height of the triangle.
 We know the angle between the base of the triangle and the hypotenuse.
 We want to find the base of the triangle.
 For this, we use the following trigonometric relationship:
 tan (70) = 39 / x
 Clearing x we have:
 x = 39 / tan (70)
 x = 14.2 feet
 Answer:
 
The distance between the base of the building and the base of the ladder is:
 
x = 14.2 feet
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Estimate the perimeter and area of the shaded figure to the nearest tenth.
Maru [420]

Answer:

Perimeter = 18.7 units

Area = 13.5 units²

Step-by-step explanation:

Perimeter of ADEC = AD + DE + EC + AC

Length of AD = 3 units

By applying Pythagoras theorem in ΔDBE,

DE² = DB² + BE²

DE² = 3² + 3²

DE = √18

DE = 4.24 units

Length of EC = 3 units

By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

AC² = 6² + 6²

AC = √72

AC = 8.49 units

Perimeter of ADEC = 3 + 4.24 + 3 + 8.49

                                 = 18.73 units

                                 ≈ 18.7 units

Area of ADEC = Area of ΔABC - Area of ΔBDE

Area of ΔABC = \frac{1}{2}(AB)(BC)

                       = \frac{1}{2}(6)(6)

                       = 18 units²

Area of ΔBDE = \frac{1}{2}(BD)(BE)

                       = \frac{1}{2}(3)(3)

                       = 4.5 units²

Area of ADEC = 18 - 4.5

                        = 13.5 units²

6 0
3 years ago
The steps below describe the construction of a line AG which is parallel to segment PQ and passes through a point A outside of P
Wittaler [7]

Answer:

“The width of the compass is adjusted to DE, and an arc is drawn from point F.”

4 0
3 years ago
Read 2 more answers
___ ÷ 4 + 3 = 9 <br> Find the missing number.
PilotLPTM [1.2K]

Answer:

The answer is 24

Step-by-step explanation:

24/4 is 6 and then you add 6 to 3 which is 9

7 0
2 years ago
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Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

We have  

Y=-\frac{1}{3}x^2-4x-5

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5

-3Y=x^2+12x+15

Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

-3Y-15=x^2+12x-15-15

-3Y-15=x^2+12x

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of x term, square it and add it both sides side.  

square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

Adding 36 to both sides.

-3Y-15+36=x^2+12x+36

-3Y+21=x^2+12x+36

Since x^2+12x+36 is a perfect square of (x+6), so, we can write as:

-3Y+21=(x+6)^2

Subtracting 21 to both sides:

-3Y+21-21=(x+6)^2-21

-3Y=(x+6)^2-21

Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
4 years ago
Find the measure of ∠ADB<br><br> ∠<br><br> A<br><br> D<br><br> B<br><br> if ∠ADC = 82°
sveta [45]
Assuming CDB is a straight line then angle ADB = 180-82=98
8 0
3 years ago
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