Answer:
Volume of HCl require = 6 mL
Explanation:
Given data:
Volume of HCl require = ?
Molarity of HCl solution = 1.60 M
Volume of NaOH = 48.0 mL
Molarity of NaOH = 0.200 M
Solution:
Formula:
M₁V₁ = M₂V₂
By putting values,
1.60 M×V₁ = 0.200 M×48.0 mL
V₁ = 0.200 M×48.0 mL/1.60 M
V₁ = 9.6 M .mL /1.60 M
V₁ = 6 mL
Mass of MnO2 = 25 g
The reaction would be 3MnO2 + 4Al --> 3Mn(s) + 2Al2O3
Molar mass of Al = 26.982 g/mol
Molar mass of MnO2 = 54.938 + 2(15.999) = 86.936 g/mol
Calculating the moles = 25 / 86.936 = 0.2876 mol.
Mole ratio MnO2 and Al considering the equation = 3 mol of MnO : 4 mol of Al
Calculating the moles of Al = 0.2876 mol MnO2 x (4 mol of Al / 3 mol of MnO)
Number of moles of Al = 0.3834
Getting the mass in grams as asked = 0.3834 mol x 26.982 g/mol = 10.34 grams.
The correct answer to this question is communicating