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3 years ago

What volume of 1.60 M hydrochloric acid solution (HCI) is required to neutralize 48.0 mL of 0.200 M sodium

Chemistry

1 answer:

nexus9112 [7]3 years ago

5 0

Answer:

Volume of HCl require = 6 mL

Explanation:

Given data:

Volume of HCl require = ?

Molarity of HCl solution = 1.60 M

Volume of NaOH = 48.0 mL

Molarity of NaOH = 0.200 M

Solution:

Formula:

M₁V₁ = M₂V₂

By putting values,

1.60 M×V₁ = 0.200 M×48.0 mL

V₁ = 0.200 M×48.0 mL/1.60 M

V₁ = 9.6 M .mL /1.60 M

V₁ = 6 mL

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In this case, it is recommended to write the enthalpy for each substance as follows:

$H_{C-6}=y_{C-6}C_v(T_b-Ti)+\Delta _vH+C_v(T_f-Tb)\\\\H_{N_2}=y_{N_2}C_v(T_f-Ti)$

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It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:

$Q=-40036+(-672.21)=-40708.21J$

Finally we convert this result to kJ:

$Q=-40708.21J*\frac{1kJ}{1000J}\\\\Q=-40.7kJ$

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