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3 years ago

What volume of 1.60 M hydrochloric acid solution (HCI) is required to neutralize 48.0 mL of 0.200 M sodium

Chemistry

1 answer:

nexus9112 [7]3 years ago

5 0

Answer:

Volume of HCl require = 6 mL

Explanation:

Given data:

Volume of HCl require = ?

Molarity of HCl solution = 1.60 M

Volume of NaOH = 48.0 mL

Molarity of NaOH = 0.200 M

Solution:

Formula:

M₁V₁ = M₂V₂

By putting values,

1.60 M×V₁ = 0.200 M×48.0 mL

V₁ = 0.200 M×48.0 mL/1.60 M

V₁ = 9.6 M .mL /1.60 M

V₁ = 6 mL

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Aleksandr [31]

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2 years ago

The Density of pure carbon in Diamond form is 3.52 g/cm^3. How many cubic inches would 23.7 moles of pure diamond occupy?

Vedmedyk [2.9K]

Answer : The volume of pure diamond is $0.493inch^3$

Explanation : Given,

Density of pure carbon in diamond = $3.52g/cm^3$

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First we have to calculate the mass of carbon or pure diamond.

$\text{ Mass of carbon}=\text{ Moles of carbon}\times \text{ Molar mass of carbon}$

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$\text{ Mass of carbon}=(23.7moles)\times (12g/mole)=284.4g$

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Formula used:

$Density=\frac{Mass}{Volume}$

Now putting all the given values in this formula, we get:

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$1cm^3=0.061inch^3$

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Volume = $0.061\times 80.8inch^3$

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3 years ago

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a_sh-v [17]

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