Question

What volume of 1.60 M hydrochloric acid solution (HCI) is required to neutralize 48.0 mL of 0.200 M sodium

Answer 1

Answer:

Volume of HCl require =  6 mL

Explanation:

Given data:

Volume of HCl require = ?

Molarity of HCl solution = 1.60 M

Volume of NaOH = 48.0 mL

Molarity of NaOH = 0.200 M

Solution:

Formula:

M₁V₁     =      M₂V₂

By putting values,

1.60 M×V₁  =  0.200 M×48.0 mL

V₁  =  0.200 M×48.0 mL/1.60 M

V₁  =  9.6 M .mL /1.60 M

V₁  =  6 mL