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3 years ago

In which of the following situations or places would you want to reduce the

Physics

1 answer:

sashaice [31]3 years ago

4 0

Answer:

Explanation:

<em>The correct answer would be in the axle of the wheels while you ride your bicycle.</em>

Options A, B, and C requires that the forces of friction is increased in order to have more control.

However, option D requires that there is a minimal frictional force in the axle of the wheels of a bicycle while riding so that a little effort would be required to keep the bicycle moving.

<u>The lesser the friction, the lower the effort that would be needed to keep the bicycle moving and vice versa.</u>

You might be interested in

Place the left charge at the 2 cm position and the right one at the 4 cm position. Vary the left and right charge to the values

Vlad1618 [11]

Answer:

Explanation:

Force between two charges can be expressed as follows

F = k q₁ q₂ / d²

q₁ and q₂ are two charges , d is distance between them , k is a constant whose value is 9 x 10⁹

distance between charges is fixed which is 4 -2 = 2 cm = 2 x 10⁻² m

force between 1μC and 4μC

= 9 x 10⁹ x 1 x 4 x 10⁻¹² / ( 2 x 10⁻² )²

= 9 x 10 = 90 N

force between 4μC and 1μC

= 9 x 10⁹ x 4 x 1 x 10⁻¹² / ( 2 x 10⁻² )²

= 9 x 10 = 90 N

force between 2μC and 2μC

= 9 x 10⁹ x 2 x 2 x 10⁻¹² / ( 2 x 10⁻² )²

= 9 x 10 = 90 N

force between 1μC and 2μC

= 9 x 10⁹ x 1 x 2 x 10⁻¹² / ( 2 x 10⁻² )²

= 4.5 x 10 = 45 N

force between 1μC and 8μC

= 9 x 10⁹ x 1 x 8 x 10⁻¹² / ( 2 x 10⁻² )²

= 18 x 10 = 180 N

force between 2μC and 8μC

= 9 x 10⁹ x 1 x 8 x 10⁻¹² / ( 2 x 10⁻² )²

= 36 x 10 = 360 N

Left Charge Right Charge Resulting force(N)

1μC 4μC 90 N

4μC 1μC 90 N

2μC 2μC 90 N

1μC 2μC 45 N

1μC 8μC 180 N

2μC 8μC 360 N

5 0

3 years ago

What's the difference between shunt and multiplier?

vovikov84 [41]

Answer:

A Shunt is a passive element, usually resistive, that is used to bypass current around another element, like a meter, that is not able to handle the full current flow. ... A Multiplier is an active element that amplifies a voltage or current to enable a less sensitive device or circuit to make use of it.

7 0

3 years ago

Read 2 more answers

You drop a stone down a well that is 19.60 m deep. How long is it before you hear the splash? The speed of sound in air is 343 m

ki77a [65]

So, the time needed before you hear the splash is approximately <u>2.06 s</u>.

<h3>Introduction</h3>

Hi ! In this question, I will help you. This question uses two principles, namely the time for an object to fall freely and the time for sound to propagate through air. When moving in free fall, the time required can be calculated by the following equation:

$\sf{h = \frac{1}{2} \cdot g \cdot t^2}$

$\sf{\frac{2 \cdot h}{g} = t^2}$

$\boxed{\sf{\bold{t = \sqrt{\frac{2 \cdot h}{g}}}}}$

With the following condition :

t = interval of the time (s)
h = height or any other displacement at vertical line (m)
g = acceleration of the gravity (m/s²)

Meanwhile, for sound propagation (without sound reflection), time propagates is the same as the quotient of distance by time. Or it can be formulated by :

$\boxed{\sf{\bold{t = \frac{s}{v}}}}$

With the following condition :

t = interval of the time (s)
s = shift or displacement (m)
v = velocity (m/s)

<h3>Problem Solving</h3>

We know that :

h = height or any other displacement at vertical line = 19.6 m
g = acceleration of the gravity = 9.8 m/s²
v = velocity = 343 m/s

What was asked :

$\sf{\sum t}$ = ... s

Step by step :

Find the time when the object falls freely until it hits the water. Save value as $\sf{\bold{t_1}}$

$\sf{t_1 = \sqrt{\frac{2 \cdot h}{g}}}$

$\sf{t_1 = \sqrt{\frac{2 \cdot \cancel{19.6} \:_2}{\cancel{9.8}}}}$

$\sf{t_1 = \sqrt{4}}$

$\sf{\bold{t_1 = 2 \: s}}$

Find the time when the sound propagate through air. Save value as $\sf{\bold{t_2}}$

$\sf{t_2 = \frac{h}{v}}$

$\sf{t_2 = \frac{19.6}{343}}$

$\sf{\bold{t_2 \approx 0.06 \: s}}$

Find the total time $\sf{\bold{\sum t}}$

$\sf{\sum t = t_1 + t_2}$

$\sf{\sum t \approx 2 + 0.06}$

$\boxed{\sf{\sum t \approx 2.06}}$

<h3>Conclusion</h3>

So, the time needed before you hear the splash is approximately 2.06 s.

3 0

2 years ago

What is number 30,31 in this picture?

Maslowich

On question 30, that is a displacement- time graph (DT). On this type of graph the gradient is equal to the velocity. B has the steepest gradient, then A and finally C

Now velocity is a vector quantity so it has a direction and speed ( speed doesn't have a fixed direction.)

on the DT graph im going to assume that movement B is a positive velocity with A and C being negative.
So by ranking these: A is the most negative, C is the least negative and B has to be the greatest as it is the only positive velocity.

Q31, The same type of graph is present, by looking at the gradients we can rank the largest and smallest velocities- speeds in the case of the question.
i'll skip my working out as its the same as before:

C, B, A and then D

the same idea as on Q30 applies to Q31 part b,

D,C,B then A

6 0

3 years ago

The lowest possible frequency that can form in a musical instrument is called the _____. A fundamental frequency B the harmonic

NeX [460]

Perhaps D. if it is the lowebsr possible frequency then it would most likely be the last. I may not be 100 percent right, but that's just an educated guess.

5 0

3 years ago