Answer:
Explanation:
a ) from San Antonio to Houston let distance be d km .
Average speed = total distance / total time
time = distance / speed
Total time = (d / 2 x 75 ) +( d / 2 x 106 )
= .0067 d + .0047 d
= .0114 d
Average speed = d / .0114 d = 87.72 km /h
b ) from Houston back to San Antonio
Total time = (d / 2 x 106 ) +( d / 2 x 75 )
= .0047 d + .0067 d
= .0114 d
Average speed = d / .0114 d = 87.72 km /h
c )
For entire trip :
total distance = 2d
total time = 2 x .0114 d
Average speed = 2 d / 2 x .0114 d
= 87.72 km /h .
Answer:
Amoebas have projections called pseudopods
Explanation:
Pseudopodia is the locomatary organ of amoeba. It helps them in movement and transportation.
Answer:
The peak wavelength of the light it irradiates decreases
Explanation:
As the temperature of a blackbody increase, the peak wavelength of the light it radiates decreases, this follows Wien's Law.
A blackbody is an ideal substance that emits all frequencies of light and also has the ability to absorb them as well.
Wiens displacement law, explains that the position of the peak wavelength of the thermal radiation emitted by bodies can change with temperature, and as the temperature increases beyond a certain point, the wavelength begins to reduce. This often changes the colour of the light emitted from heated objects.
Answer:
the point between Earth and the Moon where the gravitational pulls of Earth and Moon are equal is <em>E)3.45 × 10⁸ m</em>
Explanation:
The force that the Earth exerts on a mass m is
F_e = (G M_e m) / R_e²
where
- G is the universal gravitational constant
- M_e is the mass of Earth
- R_e is the radius of Earth
The force that the Moon exerts on a mass m is
F_m = (G M_m m) / R_m²
where
- G is the universal gravitational constant
- M_m is the mass of the Moon
- R_m is the radius of the Moon
Therefore, the point where the gravitational pulls of Earth and Moon are equal is:
F_e = F_m
R_e + R_m = R = 3.84×10⁸ m
Thus,
(G M_e m) / R_e² = (G M_m m) / R_m²
M_e / R_e² = M_m / (R - R_e²)
(R - R_e²) / R_e² = M_m / M_e
(R - R_e) / R_e = (M_m / M_e)^1/2
R_e(R/R_e -1) / R_e = (M_m / M_e)^1/2
R/ R_e = (M_m / M_e)^1/2 + 1
R_e = R / [(M_m / M_e)^1/2 + 1]
R_e = (3.84×10⁸ m) / [(7.35 x 10²² kg / 5.97 x 10²⁴ kg )^1/2 + 1]
R_e = 3.45 × 10⁸ m
Therefore, the point between Earth and the Moon where the gravitational pulls of Earth and Moon are equal is <em>3.45 × 10⁸ m.</em>
