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marissa [1.9K]
3 years ago
10

A 35 L tank of oxygen is at 315 K with an internal pressure of 190 atmospheres. How many moles of gas does the tank contain?​

Chemistry
1 answer:
VikaD [51]3 years ago
5 0
N = PV = (190 atm)(35 L) = 260 moles of gas RT (0.0821 L.atm/mol.K)(315 K)
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velikii [3]
To solve this question you need to calculate the number of the gas molecule. The calculation would be:
PV=nRT
n=PV/RT
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</span>n= 1.636 moles

The volume at bottom of the lake would be:
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meriva

Answer:

The standard enthalpy change for the reaction at 25^{0}\textrm{C} is -2043.999kJ

Explanation:

Standard enthalpy change (\Delta H_{rxn}^{0}) for the given reaction is expressed as:

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Where \Delta H_{f}^{0} refers standard enthalpy of formation

Plug in all the given values from literature in the above equation:

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alina1380 [7]

mol=35:101.11 g/mol=0.346

formula units = 0.346 x 6.02 x 10²³ = 2.082 x 10²³

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2 years ago
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