Assuming that the force of friction does not equal to the force at which you are pulling at, hence Fnet is not zero, to solve for acceleration need to use the following equation:
Fnet = ma
a = Fnet/m
a = 50 N/10 kg
a = 5 N/kg or a = 5 m/s^2.
Subtracting the mass of (flask+water) from the empty flask gives:
95.023 g - 85.135 g = 9.888 grams of water
Dividing this by the given volume of 10.00 mL water gives:
9.888 grams of water / 10.00 mL of water = 0.9888 g/mL of water
Therefore, based on this sample, the density of water is 0.9888 g/mL, which is close to the usually accepted approximation of 1 g/mL.
Based on the question, it is evident that the question is based on Boyle's Law which we will use to find the answer necessary.
Now, Boyle's Equation: P₁V₁ = P₂V₂
V₂ = P₁V₁ ÷ P₂
∴ V₂ = (12.5L × 42.0 cm · Hg) ÷ 75 cm · Hg
⇒ V₂ = 7 L
Thus, the <span>volume when the pressure has increased to 75.0 cm Hg is 7 Litres.</span>
The deeper the diver takes the helium balloon, the more it reduces in size. This is due to the pressure of the water column above pressing on the balloon. According to Boyle’s law (P= k*1/V.), as the volume of the balloon decreases, the pressure of the helium inside increases.
