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pickupchik [31]
3 years ago
12

ANSWER THESE 2 QUESTIONS AND LEAVE HOW YOU DO IT BELOW

Chemistry
2 answers:
vampirchik [111]3 years ago
5 0

Answer:

The first one is 102.33 g/ml

Explanation:

307 divided by 3 gets u the answer 102.33(repeated)

Hope this helps :)

Nikolay [14]3 years ago
3 0

Answer:

25,000g

Explanation:

Mass = density x volume

So mass = 500 x 50

That will get you 25,000 ml which you have to convert to grams and it would be 25,000 grams hope this helps

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When you apply 1000 joules of energy to 50 grams of water its temperature changes to 30 degrees . What was the initial temperatu
expeople1 [14]

Answer:

25.2°C

Explanation:

Given parameters:

Energy applied to the water  = 1000J

Mass of water  = 50g

Final temperature  = 30°C

Unknown:

Initial temperature  = ?

Solution:

To solve this problem, we use the expression below:

            H  = m c Ф

H is the energy absorbed

m is the mass

c is the specific heat capacity

Ф is the change in temperature

     1000  = 50 x 4.184 x (30  -  initial temperature )

     1000  = 209.2(30 - initial temperature)

      4.78  = 30 - initial temperature

      4.78  - 30  = - initial temperature

         Initial temperature  = 25.2°C

7 0
3 years ago
The standard cell potential (E°cell) for the reaction below is +0.63 V. The cell potential for this reaction is ________ V when
tia_tia [17]

Answer : The cell potential for this reaction is 0.50 V

Explanation :

The given cell reactions is:

Pb^{2+}(aq)+Zn(s)\rightarrow Zn^{2+}(aq)+Pb(s)

The half-cell reactions are:

Oxidation half reaction (anode):  Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction (cathode):  Pb^{2+}+2e^-\rightarrow Pb

First we have to calculate the cell potential for this reaction.

Using Nernest equation :

E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Zn^{2+}]}{[Pb^{2+}]}

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 25^oC=273+25=298K

n = number of electrons in oxidation-reduction reaction = 2

E^o_{cell} = standard electrode potential of the cell = +0.63 V

E_{cell} = cell potential for the reaction = ?

[Zn^{2+}] = 3.5 M

[Pb^{2+}] = 2.0\times 10^{-4}M

Now put all the given values in the above equation, we get:

E_{cell}=(+0.63)-\frac{2.303\times (8.314)\times (298)}{2\times 96500}\log \frac{3.5}{2.0\times 10^{-4}}

E_{cell}=0.50V

Therefore, the cell potential for this reaction is 0.50 V

5 0
3 years ago
Scenario: You are testing two different
chubhunter [2.5K]

Answer:1 × 10-8 M

Explanation:

5 0
3 years ago
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A 6-column table with 2 rows. The first column labeled number of washers has entries 1, 2. The second column labeled initial vel
Zielflug [23.3K]

Answer:

A) The acceleration due to gravity for any object, including 1 washer on the string, is always assumed to be  10  m/s2.

B) The mass of 3 washers, when converted to kg, is  0.0147  kg.

C) The applied force of 3 washers will increase the applied force on the car to 0.147 N.

Hope i helped. also can i get brainliest

8 0
3 years ago
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A fish may have hundreds of offspring at a time and only a small number can survive. which characteristics of fish might allow t
mafiozo [28]
Well depends on what type of fish the parent is but i guess you can say:
what they eat
teeth
instincts
color
venom
blending in,etc
8 0
3 years ago
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