Question

If Dante spins the spinner below 75 times, how many times should he expect it to land on "U"?​

Answer 1

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete; So, I will solve making assumptions

$Spinner = 10\ segments$

$U = 1$

$n=75$

Required

Number of times to land on U

First, calculate the theoretical probability of U

$Pr(U) = \frac{U}{Spinner}$

$Pr(U) = \frac{1}{10}$

The expected number (E) of time to land on U is then calculated as:

$E = Pr(U) * n$

$E = \frac{1}{10} * 75$

$E = 0.10 * 75$

$E = 7.5$

Approximate

$E = 8$

8 times

Follow the above steps, and you will arrive at your answer