Given:
A figure of combination of hemisphere, cylinder and cone.
Radius of hemisphere, cylinder and cone = 6 units.
Height of cylinder = 12 units
Slant height of cone = 10 units.
To find:
The volume of the given figure.
Solution:
Volume of hemisphere is:

Where, r is the radius of the hemisphere.



Volume of cylinder is:

Where, r is the radius of the cylinder and h is the height of the cylinder.



We know that,
[Pythagoras theorem]
Where, l is length, r is the radius and h is the height of the cone.

Volume of cone is:

Where, r is the radius of the cone and h is the height of the cone.



Now, the volume of the combined figure is:



Therefore, the volume of the given figure is 2110.08 cubic units.
Answer:

Step-by-step explanation:
<u>Step 1: Distribute
</u>



<u>Step 2: Distribute again
</u>
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Answer: 
For this case we must simplify the following expression:
![\sqrt [3] {64 * a ^ 6 * b ^ 7 * c ^ 9}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B64%20%2A%20a%20%5E%206%20%2A%20b%20%5E%207%20%2A%20c%20%5E%209%7D)
We rewrite:

So:
![\sqrt [3] {4 ^ 3 * (a ^ 2) ^ 3 * (b ^ 2) ^ 3 * b * (c ^ 3) ^ 3} =\\\sqrt [3] {4 * a ^ 2 * b ^ 2 * c ^ 3) ^ 3 * b} =](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B4%20%5E%203%20%2A%20%28a%20%5E%202%29%20%5E%203%20%2A%20%28b%20%5E%202%29%20%5E%203%20%2A%20b%20%2A%20%28c%20%5E%203%29%20%5E%203%7D%20%3D%5C%5C%5Csqrt%20%5B3%5D%20%7B4%20%2A%20a%20%5E%202%20%2A%20b%20%5E%202%20%2A%20c%20%5E%203%29%20%5E%203%20%2A%20b%7D%20%3D)
By definition of properties of powers and roots we have:
![\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20m%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bm%7D%20%7Bn%7D%7D)
So:
![4a ^ 2b ^ 2 c ^ 3 \sqrt [3] {b}](https://tex.z-dn.net/?f=4a%20%5E%202b%20%5E%202%20c%20%5E%203%20%5Csqrt%20%5B3%5D%20%7Bb%7D)
Answer:
Option B
Write the set of points from -6 to 0 but excluding -4 and 0 as a union of intervals
First we take the interval -6 to 0. In that -4 and 0 are excluded.
So we split the interval -6 to 0.
Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.
Interval becomes [-6,-4) . It says -6 included but -4 excluded.
Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets
(-4,0)
Now we take union of both intervals
[-6,-4) U (-4,0) --- Interval from -6 to 0 but excluding -4 and 0
Answer: I think Value of x is 8 I’m not sure