1. B) the pythagorean theorem
2. B) hypotenuse
3. I can't answer this because I don't know what the example is.
The length of the rectangular field is 120 ft if the width of a rectangular field is 20 feet less than its length and the area of the field is 12,000 ft².
<h3>What is the area of the rectangle?</h3>
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
Let's suppose the length of the rectangular field is l and the width is w.
w = l - 20
The area of the rectangular field
lw = 12000
l(l - 20) = 12000
l² - 20l - 12000 = 0
After solving the quadratic equation, we get:
l = 120 or l = -100(length cannot be negative)
Thus, the length of the rectangular field is 120 ft if the width of a rectangular field is 20 feet less than its length and the area of the field is 12,000 ft².
Learn more about the rectangle here:
brainly.com/question/15019502
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Answer:
- -25, 4, 33, 62, 91, 120, ...
Step-by-step explanation:
<h3>Given</h3>
<u>The arithmetic sequence</u>
- .. , 4, ?, ?, ?, 120, ...
<h3>To find:</h3>
<h3>Solution</h3>
<u>Let the first term a₁ = x, and common difference = d then we have:</u>
- a₁ = x
- a₂ = x + d = 4
- ...
- a₆ = x + 5d = 120
<u>The difference of the 6th and 2nd terms:</u>
- a₆ - a₂ =
- a + 5d - x - d = 120 - 4
- 4d = 116
- d = 116/4
- d = 29
<u>Then we get the first term and other missing terms:</u>
-25, 4, 4+29 = 33, 33+29 = 62, 62 + 29= 91, 91+29 = 120, ...
Answer:
The triangle EFG can be constructed with the following specifications: 
, 
, 
, 
, 
, 
.
Step-by-step explanation:
A triangle is formed by either knowing the lengths of its three sides or knowing two angles and the length of a side or knowing a angle and the lengths of two sides. By Geometry, we know that sum of internal angles in triangles equals 180°. In order to construct this triangle, we need to know the measures of angles E, F and G by means of the Law of Cosine:
Angle E
![E = \cos^{-1}\left[\frac{(7\,cm)^{2}-(12\,cm)^{2}-(8\,cm)^{2}}{-2\cdot (12\,cm)\cdot (8\,cm)} \right]](https://tex.z-dn.net/?f=E%20%3D%20%5Ccos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B%287%5C%2Ccm%29%5E%7B2%7D-%2812%5C%2Ccm%29%5E%7B2%7D-%288%5C%2Ccm%29%5E%7B2%7D%7D%7B-2%5Ccdot%20%2812%5C%2Ccm%29%5Ccdot%20%288%5C%2Ccm%29%7D%20%5Cright%5D)
Angle F
![F = \cos^{-1}\left[\frac{(12\,cm)^{2} - (8\,cm)^{2} - (7\,cm)^{2}}{-2\cdot (8\,cm)\cdot (7\,cm)} \right]](https://tex.z-dn.net/?f=F%20%3D%20%5Ccos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B%2812%5C%2Ccm%29%5E%7B2%7D%20-%20%288%5C%2Ccm%29%5E%7B2%7D%20-%20%287%5C%2Ccm%29%5E%7B2%7D%7D%7B-2%5Ccdot%20%288%5C%2Ccm%29%5Ccdot%20%287%5C%2Ccm%29%7D%20%5Cright%5D)
Angle G
![G = \cos^{-1}\left[\frac{(8\,cm)^{2}-(12\,cm)^{2}-(7\,cm)^{2}}{-2\cdot (12\,cm)\cdot (7\,cm)} \right]](https://tex.z-dn.net/?f=G%20%3D%20%5Ccos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B%288%5C%2Ccm%29%5E%7B2%7D-%2812%5C%2Ccm%29%5E%7B2%7D-%287%5C%2Ccm%29%5E%7B2%7D%7D%7B-2%5Ccdot%20%2812%5C%2Ccm%29%5Ccdot%20%287%5C%2Ccm%29%7D%20%5Cright%5D)
The triangle EFG can be constructed with the following specifications: , , , , , .
Answer:
Decrease number by 2,155.44% of its value.
Percentage decrease = 2,155.44% × 18.5
