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3 years ago

Which of the polygons can always be classified as a rhombus?

Mathematics

2 answers:

Ainat [17]3 years ago

8 0

Answer:

Step-by-step explanation:

Svetach [21]3 years ago

6 0

C is the answer I think if I’m wrong sorry

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The lengths of two sides of a triangle are shown below:

Feliz [49]

Answer:

Part A) $(3x^2 - 6x - 10) + (5x^2 + 9x - 8 ) =8x^2 + 3x - 18$

Part B) $(10x^2 - x - 3) - (8x^2+3x-18) = 2x^2 -4x+15$

3 0

3 years ago

Consider the initial value problem:

Inessa [10]

Answer:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

Step-by-step explanation:

The given initial value problem is;

$y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2$

Let

$u(t)=y(t)----(2)\\v(t)=y'(t)----(3)$

Differentiating both sides of equation (1) with respect to $t$ , we obtain:

$u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)$

Differentiating both sides of equation (2) with respect to $t$ gives:

$v'(t)=y''(t)----(6)$

From equation (1),

$y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)$

Putting t=0 into equation (2) yields

$u(0)=y(0)\\\implies u(0)=-5$

Also putting t=0 into equation (3)

$u'(0)=y'(0)\\u'(0)=2$

The system of first order equations is:

$\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2$

3 0

3 years ago

there are 90 kids in the band. 20% of the kids own their own instruments, and the rest rent them. how many kids own their own in

lawyer [7]

Answer:

18 kids

Step-by-step explanation:

6 0

3 years ago

Find the exact value of sin ( 7 π 4 ) using reference angles

Firdavs [7]

Answer:

-1/root2

Step-by-step explanation:

7pi/4 radians is the same as -pi/4 radians

sin(-pi/4) is -sin(pi/4) = -1/root2

3 0

3 years ago

The function y = f (x) is graphed below. What is the average rate of change of the function f(x) on the interval - 1 ≤ x ≤ 3?

jonny [76]

Answer:

$\displaystyle -2$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Average Rate of Change: $\displaystyle \frac{f(b) - f(a)}{b - a}$

Step-by-step explanation:

Step 1: Define

Interval -1 ≤ x ≤ 3

a = -1, b = 3

f(a) = f(-1) = 4

f(b) = f(3) = -4

Step 2: Find Average

Substitute in variables [ARC]: $\displaystyle \frac{f(3) - f(-1)}{3 + 1}$
Substitute: $\displaystyle \frac{-4 - 4}{3 + 1}$
[Fraction] Subtract/Add: $\displaystyle \frac{-8}{4}$
[Fraction] Divide: $\displaystyle -2$

4 0

3 years ago