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3 years ago

Water has density of 1.0 g/L. What volume of water has mass 250 g?

Chemistry

1 answer:

schepotkina [342]3 years ago

4 0

Answer:

Examine the units: If the density is 1 g/mL, how many mL do you need to make 250 g?

X mL * 1 g/mL = 250 g

Solve for X

x mL = 250 g / 1 g/mL = 250 mL

Hope this helps :)

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Which of the following elements would be likely to form an anion?

Vsevolod [243]

B because chlorine is a halogen. This means that it already 7 valence electrons and only needs 1 more to have a complete outer shell.

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3 years ago

how many grams of fertilizer , for potassium sulfate are there in 42.3 mole of potassium sulfate? step by step

Over [174]

Answer:

The mass of 42.3 moles of potassium sulfate is 7,371.1557 grams

Explanation:

Potassium sulfate K₂SO₄ which is also known as sulphate of potash is a water soluble common component of fertilizer

The molar mass of potassium sulfate, M = 174.259 g/mol

The given number of moles of potassium sulfate, n = 42.3 moles

The mass, 'm', of a given number of moles of potassium sulfate, 'n', is given as follows;

m = n × M

Therefore, we have;

The mass, 'm', of 42.3 moles of potassium sulfate is found by plugging in the values for 'M', and 'n', in the above equation as follows;

m = 42.3 moles × 174.259 g/mol = 7,371.1557 grams

The mass of 42.3 moles of potassium sulfate, m = 7,371.1557 grams.

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3 years ago

Which rock type is most likely to compsoed of just one mineral?

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maybe is answer is rhyolite

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3 years ago

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PLEASE HELP Describe at least two advantages and two disadvantages of using hydropower as a

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Answer:

Advantage: Hydropower is a fueled by water, so it's a clean fuel source.

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Disadvantage: Fish populations can be impacted if fish cannot migrate upstream past impoundment dams to spawning grounds or if they cannot migrate downstream to the ocean.

Disadvantage: Hydropower plants can be impacted by drought. When water is not available, the hydropower plants can't produce electricity.

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3 years ago

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Answer:

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Explanation:

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Let the molecular formula of estradiol be $C_xH_yO_z$

Percentage of an element in a compound:

$\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100$

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$\frac{x\times 12 g/mol}{272.37 g/mol}\times 100=79.37\%$

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Percentage of oxygen in estradiol :

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3 years ago