40×19.32/100=7.7=8×2=16Ca
35.5×34.30/100=12.1=12×2=24Cl
16×46.38/100=7.4=7×2=14O
The remaining moles of C is 5.01 moles while the remaining moles of F₂ is 0.
<h3>
Reaction between Carbon and Fluorine </h3>
The reaction between carbon and Fluorine is given as;
C + 2F₂ -------> CF₄
1 : 2 1
from the reaction above,
2 moles of F₂ requires 1 mole of C
7.88 mole of F₂ will require: 7.88/2 = 3.94 moles of C and 3.94 moles of CF₄.
The remaining moles of C = 8.95 - 3.94 = 5.01 moles while the remaining moles of F₂ is 0.
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Answer:
Explanation:
Given the details, we can say that
Pure methanol is a volatile solvent as the vapour pressure has a high value. This means that methanol - methanol intermolecular forces are weak in comparisson to water - water forces. When having about 30% of water in a methanol mixture, the mixture Pv decreased, showing that it is not a volatile mixture, so then there are strong intermolecular interactions between methanol - water, part of it due to the hydrogen bonds.
Explanation:
Once solid ammonium nitrate interacts with water, the molecules of polar water intermingle with these ions and attract individual ions from the structure of the lattice, that actually will break down. E.g;-NH4NO3(s) — NH4+(aq)+ NO3-(aq) To split the ionic bonds that bind the lattice intact takes energy that is drained from the surroundings to cool the solution.
Some heat energy is produced once the ammonium and nitrate ions react with the water molecules (exothermic reaction), however this heat is far below that is needed by the H2O molecules to split the powerful ionic bonds in the solid ammonium nitrate.
Hence, we can say that the dissolution of ammonium nitrate in water is highly endothermic reaction.
