Answer:
= - 303.975 Joules
Explanation:
Given that:
The volume of the cylinder = 0.003 m^3
Now, to liters:
The volume = 0.003 *1000 L
= 3 L
For an open cylinder, we mean the atmospheric pressure is at standard condition.
Thus, the workdone = -PΔV
= - 1 atm (3 L)
= - 3 L atm
1 L atm to Joules
= 101.325 Joules
Therefore;
=- 3* 101.325 Joules
= - 303.975 Joules
Answer:
It can be expressed in several ways: molarity (moles of solute per liter of solution); mole fraction, the ratio of the number of moles of solute to the total number of moles of substances present; mass percentage, the ratio of the mass of the solute to the mass of the solution times 100; parts per thousand (ppt), grams ...
Explanation:
It can be expressed in several ways: molarity (moles of solute per liter of solution); mole fraction, the ratio of the number of moles of solute to the total number of moles of substances present; mass percentage, the ratio of the mass of the solute to the mass of the solution times 100; parts per thousand (ppt), grams ...
Answer:
"1 M" will be the right solution.
Explanation:
The given values are:
Number of moles,
= 2 moles
Volume of solution,
= 2000 mL
or,
= 2 L
Now,
The molarity of the solution will be:
= 
On substituting the values, we get
= 
= 
Answer:
a) CH4 (g) (1 mole) + H2O (g) (1 mole) = CO (g) + 3H2 (g) (3 moles).
b) 3/1 or 3 will be the conversion factor used to convert moles of methane and the moles of hydrogen.
c) Based on the given mole-mole relation,
The number of moles of hydrogen produced by 1 mole of CH4 or methane is 3 moles. Therefore, the number of moles of hydrogen produced from 7 moles of CH4 would be,
3/1 * 7 = 21 moles.
d) The formation of 3 moles of hydrogen is taking place from 1 mole of water vapor or H2O. Therefore, the number of moles of water vapor required to produced 100.50 moles of hydrogen would be,
1/3 * 100.50 moles = 33.5 moles.
sound is a wave passing through air.
