3 years ago

3. 5x² + 13x = -6 * SHOW WORK *

Mathematics

1 answer:

Orlov [11]3 years ago

6 0

For solving steps use photomath

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If the current in a circuit is 2 +j2 amps and the resistance is 3-j2 ohms, what is the voltage

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Answer:

The voltage is 10 + 2j volts.

Step-by-step explanation:

Ohm's first law:

By Ohm's first law, the voltage is the multiplication of the current by the resistance, that is:

$V = R*i$

The voltage is measured in Volts, the current in amps and the resistance in ohms.

In this question:

Both the current and the resistance have complex parts. We have to know that:

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Then

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$V = 6 + 2j - 4(-1)$

$V = 10 + 2j$

The voltage is 10 + 2j volts.

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Step-by-step explanation:

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