Suppose you have a 115 kg wooden crate resting on a wood floor, with coefficient of static friction 0.500 between these wood sur
1 answer:
Answer:
maximum force (in N) can you exert horizontally on the crate without moving it = 564.075 N
Explanation:
Given data:
mass m= 115 kg
coefficient of friction μ =0.5
according to newton law of motion the net force acted on body is given by
here the body is in rest ,
N= it is the normal reaction force
N= mg = 115×9.81
therefore,
You might be interested in
Answer:
the thickness of the soap film is 127.82 nm or 130 nm
Explanation:
Given the data in the question;
n = 1.33
λ = 680 nm = 680 × 10⁻⁹ m
m = 1 and β = 0
When we see the red fringe, its a point of maximum reflection
hence, for interference with a thin soap film, we say;
2 × n × d × cos( β ) = ( m - 0.5) × λ
so we substitute in our given values;
2 × 1.33 × d × cos( 0 ) = ( 1 - 0.5) × ( 680 × 10⁻⁹ )
2.66 × cos( 0 ) × d = 0.5 × ( 680 × 10⁻⁹ )
2.66 × 1 × d = 3.4 × 10⁻⁷
d = ( 3.4 × 10⁻⁷ ) / 2.66
d = 127.82 × 10⁻⁹ m
d = 127.82 nm ≈ 130 nm
Therefore, the thickness of the soap film is 127.82 nm or 130 nm
Answer:B)439.21 Hz
Explanation:
Given
velocity of train
frequency of train
speed of sound
frequency from Doppler effect can be calculated by