Answer:
Magnitude of the net force acting on the kayak = 39.61 N
Explanation:
Considering motion of kayak:-
Initial velocity, u = 0 m/s
Distance , s = 0.40 m
Final velocity, v = 0.65 m/s
We have equation of motion v² = u² + 2as
Substituting
v² = u² + 2as
0.65² = 0² + 2 x a x 0.4
a = 0.53 m/s²
We have force, F = ma
Mass, m = 75 kg
F = ma = 75 x 0.53 = 39.61 N
Magnitude of the net force acting on the kayak = 39.61 N
If an object is on a frictionless surface, to keep it at a constant velocity you can’t apply any force because otherwise, the object will accelerate, and the velocity will change.
I'm pretty sure it's the<span> impact of the air molecules on the outside of the stopper. They exert a net inward force, which is not resisted by anything on the other side.</span>
Answer:
17 m/s
Explanation:
Using formula a = (v-u) /t
acceleration a = -1.5 m/s2
final velocity v = unknown
initial velocity u = 32 m/s
time t = 10s
-1.5 = (v-32)/10
-15 = v - 32
-15 + 32 = v
v = 17 m/s
