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Virty [35]
3 years ago
8

Write in scientific notation: 2540 X 10​

Mathematics
1 answer:
Vlada [557]3 years ago
6 0

Answer:

2.54×10⁴

Step-by-step explanation:

2540×10

*convert to standard form and if the bases are same add the powers

2.54×10³×10¹

=2.54×10⁴

*zeros after the decimal points are not consider

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You want to estimate the mean weight loss of people one year after using a popular weight-loss program being advertised on TV. H
maria [59]

Answer:

At least 6907 people.

Step-by-step explanation:

Population std deviation = sigma= 10.6

Since population std deviation is known, we can use normal probability table to get sample size from confidence interval.

The sample mean weight loss is within 0.25 lb of the true population mean.

Hence  margin of error < 0.25

Margin of error = z critical (std dev/n) where n = sample size

Z critical for 95% = 1.96

Hence 0.25 >1.96(10.6)/sq rt n

Simplify to get

sq rt n > 1.96(10.6)/0.25 = 83.104

Square both the sides to get

n > 83.104 square = 6906.27

i.e. sample size should be atleast 6907.

3 0
3 years ago
6) y = -5(x + 7)<br> Is it linear
Firdavs [7]

Answer:yes

Step-by-step explanation:

It has the y=mx+b format

5 0
3 years ago
!15 points!
lina2011 [118]

Sum of complement angles = 90

<L + <M = 90

3x - 15 + x = 90

4x - 15 = 90

4x = 105

x = 26.25


<L = 3(18.5) - 15

<L = 63.75


Answer

<L = 63.75°

5 0
4 years ago
PLEASE HELP, ASAP!
Harlamova29_29 [7]
27.75 hope it helps!
8 0
3 years ago
Read 2 more answers
What is the solution to the equation below? √ x-5 = x-11
Anuta_ua [19.1K]

Answer:

x= 14

Step-by-step explanation:

sqrt( x-5) = x-11

Square each side

(sqrt( x-5))^2 = (x-11)^2

x-5 = x^2 - 22x +121

Subtract (x-5) from each side

x-5-x+5 = x^2 -22x +121 -x+5

0 = x^2 -23x +126

Factor

0 = ( x-14) ( x-9)

Using the zero product property

x-14 = 0   x-9=0

x=14 x=9

Check the solutions

sqrt( x-5) = x-11

sqrt( 14-5) = 14-11

sqrt(9) = 3

3=3

solution

sqrt( x-5) = x-11

sqrt(9-5) = 9-11

sqrt(4) =-2

2 = -2

not a solution

6 0
3 years ago
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