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scZoUnD [109]
3 years ago
15

the small electric shock you feel when you rub your shoes on carpet and touch something metal is caused by..?1. direct current2.

induction3. conduction
Physics
2 answers:
olasank [31]3 years ago
7 0

Answer:

conduction

Explanation:

It is due to the conduction.

When the charge flows through a conductor, you get a small shock.

vovikov84 [41]3 years ago
5 0

Answer:

1. direct current  2. induction  3. conduction

Explanation:

When we walk barefoot on a carpet there is friction between the carpet surface and the lower surface of the feet which results in the exchange of charges between the two surfaces. During this course the carpet loses electron to the surface of the foot. Now, the charge on the carpet is static because it is an insulator but a human body being a good conductor of electricity has mobility of the charges.(3)

These mobile charges on the surface of a human body spread and look for a path of dissipation to a reservoir. When we bring our hand near a metal it induces an opposite charge near the surface of the metal,(2) this happens within a fraction of seconds. Now there is a positive charge on the nearest point on the metal and the negative charge on its farthest end is induced according to the conservation of charges.

As soon as the hand touches the metal (1)there is a transfer of charge from our body to the metal generating a very small shock. This happens only if we continue to stand on an insulated surface due to which the charge doesn't gets transferred to the ground.

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A vector has a component of 10 m in the x-direction, a component of 10 m in the y-direction, and a component of 5 m in the z dir
Kobotan [32]

The magnitude of this vector is 15

A vector is a quantity or phenomenon that has two independent properties: magnitude and direction. The term also denotes the mathematical or geometrical representation of such a quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.

The magnitude of a vector formula is used to calculate the length for a given vector (say v) and is denoted as |v|. So basically, this quantity is the length between the initial point and endpoint of the vector.

Let vector be = a

component of vector in x direction = 10 i

component of vector in y direction = 10 j

component of vector in z direction = 5 z

vector a = 10 i + 10 j + 5 z

magnitude of vector a = |a| = \sqrt{10^{2} +10^{2} + 5^{2}    }

                                             = 15

To learn more about vector here

brainly.com/question/24256726

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8 0
2 years ago
Dr. John Paul Stapp was U.S. Air Force officer whostudied the effects of extreme deceleration on thehuman body. On December 10,
Ira Lisetskai [31]

Answer:

(a) a = 56.4 m/s², his acceleration a, in multiples of gravity g, is 5.76 g

(b) a = -201.43 m/s², his deceleration -a, in multiples of gravity g, is -20.56 g

Explanation:

(a)

When moving upwards, the initial velocity, u = 0 (he accelerated from rest)

When moving upwards, the final velocity, v = 282 m/s

time of  motion during this acceleration, t = 5 s

His acceleration is calculated as;

v = u + at

282 = 0 + 5a

a = 282 / 5

a = 56.4 m/s²

Ratio of his acceleration, a to gravity, g = a/g = 56.4 / 9.8 = 5.76

a = 5.76 g

(b)

When moving downwards, the initial velocity, u = 282 m/s

When moving downwards, the final velocity, v = 0 (he was brought to rest)

time of  motion during this deceleration, t = 1.4 s

His deceleration is calculated as;

v = u + at

0 = 282 + 1.4a

1.4a = -282

a = -282 / 1.4

a = -201.43 m/s²

Ratio of his deceleration, -a to gravity, g = -a/g = 201.43 / 9.8 = 20.56

a = -20.56 g

3 0
3 years ago
A 60 cm diameter wheel accelerates from rest at a rate of 7 rad/s2. After the wheel has undergone 14 rotations, what is the radi
Mamont248 [21]

Answer:

a=368.97\ m/s^2

Explanation:

Given that,

Initial angular velocity, \omega=0

Acceleration of the wheel, \alpha =7\ rad/s^2

Rotation, \theta=14\ rotation=14\times 2\pi =87.96\ rad

Let t is the time. Using second equation of kinematics can be calculated using time.

\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\\t=\sqrt{\dfrac{2\theta}{\alpha }} \\\\t=\sqrt{\dfrac{2\times 87.96}{7}} \\\\t=5.01\ s

Let \omega_f is the final angular velocity and a is the radial component of acceleration.

\omega_f=\omega_i+\alpha t\\\\\omega_f=0+7\times 5.01\\\\\omega_f=35.07\ rad/s

Radial component of acceleration,

a=\omega_f^2r\\\\a=(35.07)^2\times 0.3\\\\a=368.97\ m/s^2

So, the required acceleration on the edge of the wheel is 368.97\ m/s^2.

6 0
3 years ago
Five hundred joules of heat are added to a closed system. The initial internal energy of the system is 87 J, and the final inter
mina [271]
The answer is D. i got all the other ones wrong ._.

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How much power does device use that is plugged into an outlet with a voltage difference of 150 V if the current is 15 A? Show me
Alexeev081 [22]

Answer:

Power used = VI

= 150 x 15

= 2250 W

Hope this helps!

5 0
3 years ago
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