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kaheart [24]
3 years ago
14

How can you tell if high frequency noise is present in your sound signal without playing it back?

Physics
1 answer:
frutty [35]3 years ago
6 0

You can look at the acoustic wave of the sound signal

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Which temperature is lower ? -44°c -55°c​
Mice21 [21]

Answer:

-55 degrees c

Explanation:

because negative numbers work in reverse and that makes -55 actually lower.

6 0
3 years ago
A ball of mass 0.200kg with a velocity of 1.50i^m/s meets a ball of mass 0.300kg with a velocity of -0.400 i^ m/s in a head-on,
Monica [59]

Velocities of their center of mass after collisions are found by the following formula as shown in the image:

<h3>What are elastic collisions?</h3>
  • An elastic collision is one in which there is no energy lost during the impact. A moderately inelastic collision occurs when some energy is wasted yet the items do not cling together. The maximum amount of energy is wasted when the objects collide in a perfectly inelastic impact. The kinetic energy doesn't change.
  • It may be two dimensions or one dimension. Because there will always be some energy exchange, no matter how tiny, totally elastic collision is not conceivable in the real world.
  • While the overall system's linear momentum does not change, the individual momenta of the participating components do, and because these changes are equal and opposite in size and cancel each other out, the initial energy is conserved.

To learn more about Elastic collisions refer to:

brainly.com/question/2356330

#SPJ4

4 0
2 years ago
15 points
Marizza181 [45]
Basaltic magma is the A. The least explosive type of magma.
6 0
3 years ago
Playing with a stress ball you squeeze it as
shutvik [7]

Answer:

it dies

Explanation:

MWUAHHAHAHHA

8 0
3 years ago
A girl weighing 600 N steps on a bathroom scale that contains a stiff spring. In equilibrium, the spring is compressed 1.0 cm un
8_murik_8 [283]

Answer:

The spring constant is 60,000 N

The total work done on it during the compression is 3 J

Explanation:

Given;

weight of the girl, W = 600 N

compression of the spring, x = 1 cm = 0.01 m

To determine the spring constant, we apply hook's law;

F = kx

where;

F is applied force or weight on the spring

k is the spring constant

x is the compression of the spring

k = F / x

k = 600 / 0.01

k = 60,000 N

The total work done on the spring = elastic potential energy of the spring, U;

U = ¹/₂kx²

U = ¹/₂(60000)(0.01)²

U = 3 J

Thus, the total work done on it during the compression is 3 J

3 0
3 years ago
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