Question

What is the energy of a 933 nm wave?

Answer 1

E=hc/l

E=

E=(6.626 x 10-34 J s)(3.0 x 108m/s )=2.88 x 10-19J6.90 x 10-7m

Answer 2

Answer: $0.02130\times 10^{-17}Joules$

Explanation:

$E=\frac{hc}{\lambda}$

E= energy

h = Planck's constant = $6.626\times 10^{-34}Js$

c = speed of light =$3\times 10^8ms^{-1}$

$\lambda$ = Wavelength of radiation = 933 nm =$933\times 10^{-9}m$

Now put all the given values in this formula, we get

$E=\frac{6.626\times 10^{-34}Js\times 3\times 10^8ms^{-1}}{933\times 10^{-9}m}$

$E=0.02130\times 10^{-17}Joules$

Thus energy of a 933 nm wave is $0.02130\times 10^{-17}Joules$