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3 years ago

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1 answer:

4 0

You can conclude that your substance is a solid because of the slow moving particles and their being little space for those particles to be moving around.

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g For the following reaction, 5.07 grams of nitrogen gas are allowed to react with 5.40 grams of hydrogen gas . nitrogen(g) + hy

galben [10]

Answer:

6.16 grams of NH3 will be produced. N2 is the limiting reactant. H2 is in excess, there will remain 4.30 grams of H2

Explanation:

Step 1: Data given

Mass of nitrogen gas(N2) = 5.07 grams

Mass of hydrogen gas (H2)

Molar mass N2 = 28.0 g/mol

Molar mass H2 = 2.02 g/mol

Step 2: The balanced equation

N2(g) + 3H2(g) → 2NH3(g)

Step 3: Calculate moles

Moles = mass / molar mass

Moles N2 = 5.07 grams / 28.0 g/mol

Moles N2 = 0.181 moles

Moles H2 = 5.40 grams / 2.02 g/mol

Moles H2 = 2.67 moles

Step 4: Calculate the limiting reactant.

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

N2 is the limiting reactant. It will completely be consumed (0.181 moles). H2 is in excess. There will react 3*0.181 = 0.543 moles

There will remain 2.67 - 0.543 = 2.127 moles

Step 5: Calculate mass of H2 that remains

Mass H2 = 2.127 moles * 2.02 g/mol

Mass H2 = 4.30 grams

Step 6: Calculate moles ammonia

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 0.181 moles N2 we need 2*0.181 = 0.362 moles NH3

Step 7: Calculate mass NH3

Mass NH3 = moles NH3 * molar mass NH3

Mass NH3 = 0.362 moles * 17.01 g/mol

Mass NH3 = 6.16 grams

6.16 grams of NH3 will be produced. N2 is the limiting reactant. H2 is in excess, there will remain 4.30 grams of H2

6 0

3 years ago

Newtons’ THIRD Law of Motion

maksim [4K]

the second one is equal and opposite

6 0

3 years ago

[cu(nh3)4]2 forms a blue solution. when concentrated hcl is added to this solution, what color will the solution change to

g100num [7]

<span>[Cu(NH3)4]2+ forms a blue solution. When concentrated HCl is added to this solution, what color will the solution change to yellow.

Reason:
When conc. HCl is added to the solution containing </span>[Cu(NH3)4]2+, Cl- ions will replace NH3 and form [Cu(Cl)4]2- complex. This can be understood for the following reaction:

[Cu(NH3)4]2+ + Cl- ↔ [Cu(Cl)4]2- + NH3

The Cl- ion is a weak field ligand, while NH3 is a strong field ligand. Hence, Cl- will in less splitting of d-orbitals, as compared to NH3. Due to this, photons of different energies will be absorbed by these complexes, and hence they display different colours.

8 0

3 years ago

Read 2 more answers

If f(x)=x^2 and g(x)=2x+3, what is f(g(x))

IgorC [24]

Answer:

$\huge\boxed{f(g(x)) = 4x^2 + 12x + 9}$

Explanation:

In its raw form, function notation essentially represents an equation with only one unknown variable, expressed in terms of another. Thus, f(x) = x² + 7x can be expressed as

g(x) = 2x + 3

f(g(x)) = (2x + 3)²

f(g(x)) = 4x² + 12x + 9

Hope it helps :) and let me know if you want me to elaborate.

6 0

3 years ago

Read 2 more answers

HELP ASAP 20 POINTS

Colt1911 [192]

Solubility of a compound in water can be referred to as the amount of the compound that can be dissolved in 1 L of the solvent (water) at any given temperature. Solubility of a compound can be expressed in the units of g/L or mg/L.

Given that the solubility of calcium carbonate in water = 14 mg/L

We have to calculate the volume of water that can dissolve 11 g of calcium carbonate.

Converting 11 g calcium carbonate to mg:

$11g *\frac{1000mg}{1g} =11,000 mg$

Volume of water that would dissolve 11000 mg calcium carbonate

= $11000 mg CaCO_{3}*\frac{1L}{14 mg}$

=785.7 L

Rounding the volume 785.7 L to two significant figures, we get 790 L water.

Therefore, we would need 790 L water to completely dissolve 11 g of calcium carbonate.

4 0

3 years ago