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katovenus [111]
3 years ago
5

ammonia, NH3 is an important industrial chemical. it is produced using the haber process from nitrogen, N2 and hydrogen, H2. how

much ammonia can be produced from 28 kg of nitrogen and 2 kg of hydrogen, assuming the reaction yield is 90%
Chemistry
1 answer:
Korvikt [17]3 years ago
4 0

Answer:

mass of ammonia = 10.090 kg

Explanation:

We have the following chemical reaction:

N₂ + 3 H₂ → 2 NH₃

number of moles = mass / molecular weight

number of moles of N₂ = 28 / 14 = 2 kmoles

number of moles of H₂ = 2 / 2 = 1 kmole

We see that the limiting reactant is hydrogen (H₂).

Now we devise the following reasoning:

if        3 kmoles of hydrogen produces 2 kmoles of ammonia

then  1 kmole of hydrogen produces X kmoles of ammonia

X = (1 × 2) / 3 = 0.66 kmoles of ammonia

But the yield is 90% so the real quantity of ammonia produced is:

(90/100) × 0.66 = 0.594 kmoles of ammonia

mass = number of moles × molecular weight

mass of ammonia = 0.594 × 17 = 10.090 kg

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katovenus [111]

Answer:

IDK

Explanation:

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6 0
4 years ago
How many electrons are in the 3p sublevel of Sulfur?
goldenfox [79]
There are FOUR electrons in the 3p sub-level of sulfur....
3 0
3 years ago
A piece of copper absorbs 5000 J of energy and undergoes a temperature change from 100 °C to 200 °C. What is the mass of the pie
irakobra [83]

Answer:

B.) 129.9 grams

Explanation:

To find the mass, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

The specific heat of copper is 0.385 J/g°C. Knowing this, you can plug the given values into the equation and simplify to isolate "m".

Q = mcΔT                                                            <----- Equation

5000 J = m(0.385 J/g°C)(200 °C - 100 °C)        <----- Insert values

5000 J = m(0.385 J/g°C)(100)                            <----- Subtract

5000 J = m(38.5)                                                <----- Multiply 0.385 and 100

129.9 = m                                                             <----- Divide both sides by 38.5

8 0
2 years ago
What volume of benzene (C6H6, d= 0.88 g/mL, molar mass = 78.11 g/mol) is required to produce 1.5 x 103 kJ of heat according to t
Anton [14]

Answer:

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

Explanation:

<u>Step 1:</u> Data given

Density of benzene = 0.88 g/mL

Molar mass of benzene = 78.11 g/mol

Heat produced = 1.5 * 10³ kJ

<u>Step 2:</u> The balanced equation

2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g)         ΔH°rxn = -6278 kJ

<u>Step 3:</u> Calculate moles of benzen

1.5 * 10³ kJ * (2 mol C6H6 / 6278 kJ) = 0.478 mol C6H6

<u>Step 4:</u> Calculate mass of benzene

Mass benzene : moles benzene * molar mass benzene

Mass benzene= 0.478 * 78.11 g

Mass of benzene = 37.34 grams

<u>Step 5:</u> Calculate volume of benzene

Volume benzene = mass / density

Volume benzene = 37.34 grams / 0.88g/mL

Volume benzene = 42.4 mL

We need 42.4 mL of benzene to produce 1.5 *10³ kJ of heat

4 0
3 years ago
Four conditions which cause a metathesis reaction to occur?
zubka84 [21]
Metathesis is a type of reaction in which the cations and anions exchange partners. this reaction is also called double replacement. Metathesis reactions are driven by the formation of a product .this reaction is classified into three different categories: formation of precipitate, f<span>ormation of a Weak or Non-electrolyte and production of the gas.</span>
4 0
3 years ago
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