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arsen [322]
3 years ago
5

How many molecules is 1.50 moles of CO2

Chemistry
1 answer:
stealth61 [152]3 years ago
5 0

Answer:

The answer to your question is 9.034 x 10²³ molecules

Explanation:

Data

number of molecules = ?

number of moles = 1.50

Process

To solve this problem, use Avogadro's number. This number relates 1 mol of a substance to 6.023 x 10²³ molecules.

                          1 mol of CO₂ ---------------  6.023 x 10 ²³ molecules

                          1.5 moles of CO₂ ----------   x

                                x = (1.5 x 6.023 x 10²³) / 1

                                x = 9.034 x 10²³ molecules

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A 2.684-g sample of zinc oxide was reduced by hydrogen gas, resulting in 2. 156 g of pure zinc metal. Determine the empirical fo
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The empirical formula of the initial zinc oxide is ZnO.

<h3>What is Empirical Formula?</h3>

The empirical formula of a compound represents the ratios of elements in a compound but not the actual numbers or arrangement of the atoms.

It is the lowest whole number ratio of the element in the compound.

<h3>How to find out the empirical formula?</h3>
  • Find out the given masses and molar masses of the elements

The molar mass of Zn = 65 gmol⁻¹

Given the mass of Zn = 2.156 g

The molar mass of Oxygen = 16 gmol⁻¹

The mass of Oxygen = Mass of a sample of zinc oxide - the mass of zinc metal

                                   = (2.684 - 2.156) g

                                   = 0.528 g

  • Find the number of moles of the elements in the compound

The number of moles is given by

n = \frac{m}{M}

where m = given mass and

M = Molar mass

Number of moles of Zinc = \frac{2.156}{65} = 0.033 moles

Number of moles of Oxygen =\frac{0.528}{16} = 0.033 moles

  • Find the simplest ratios of the elements in the compound. To find the ratios simply divide the number of moles by the lowest number of moles obtained.

Here, the number of moles is the same for both elements. Hence, the simplest ratio for Zn:O is 1:1.

Therefore, the empirical formula of zinc oxide is ZnO.

Learn more about the empirical formula:

brainly.com/question/1603500

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5 0
1 year ago
Which ancient African Kingdom is located in western Africa? ​
NISA [10]

Answer:

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3 years ago
If nitrogen-13 has a half life of 2.5 years, how much remains from a 100g sample after 7.5 years
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Answer:

12.50g

Explanation:

T½ = 2.5years

No = 100g

N = ?

Time (T) = 7.5 years

To solve this question, we'll have to find the disintegration constant λ first

T½ = In2 / λ

T½ = 0.693 / λ

λ = 0.693 / 2.5

λ = 0.2772

In(N/No) = -λt

N = No* e^-λt

N = 100 * e^-(0.2772*7.5)

N = 100*e^-2.079

N = 100 * 0.125

N = 12.50g

The sample remaining after 7.5 years is 12.50g

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3 years ago
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Answer:

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