Answer:
pH at equivalence point is 8.52
Explanation:

1 mol of HCOOH reacts with 1 mol of NaOH to produce 1 mol of 
So, moles of NaOH used to reach equivalence point equal to number of moles
produced at equivalence point.
As density of water is 1g/mL, therefore molarity is equal to molality of an aqueous solution.
So, moles of
produced = 
Total volume of solution at equivalence point = (25+29.80) mL = 54.80 mL
So, at equivalence point concentration of
= 
At equivalence point, pH depends upon hydrolysis of
. So, we have to construct an ICE table.

I: 0.1940 0 0
C: -x +x +x
E: 0.1940-x x x
So, ![\frac{[HCOOH][OH^{-}]}{[HCOO^{-}]}=K_{b}(HCOO^{-})=\frac{10^{-14}}{Ka(HCOOH)}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BHCOOH%5D%5BOH%5E%7B-%7D%5D%7D%7B%5BHCOO%5E%7B-%7D%5D%7D%3DK_%7Bb%7D%28HCOO%5E%7B-%7D%29%3D%5Cfrac%7B10%5E%7B-14%7D%7D%7BKa%28HCOOH%29%7D)
species inside third bracket represent equilibrium concentrations
So, 
or,
So, 
So, 
So, ![pH=14-pOH=14+log[OH^{-}]=14+logx=14+log(3.285\times 10^{-6})=8.52](https://tex.z-dn.net/?f=pH%3D14-pOH%3D14%2Blog%5BOH%5E%7B-%7D%5D%3D14%2Blogx%3D14%2Blog%283.285%5Ctimes%2010%5E%7B-6%7D%29%3D8.52)
Answer:
When the forest burns we will lose a huge amount of oxygen and animals will lose their home.
Explanation:
Initiation <span>occurs when mRNA, tRNA, and an amino acid meet up inside the ribosome. </span>Elongation occurs when amino acids are continually added to the line, forming a long chain bound together by peptide bonds.
The answer is: lose electrons and form positive ions.
Most metals have strong metallic bond, because of strong electrostatic attractive force between valence electrons (metals usually have low ionization energy and lose electrons easy) and positively charged metal ions.
The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).
For example, magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.
Electron configuration of magnesium ion: ₁₂Mg²⁺ 1s² 2s² 2p⁶.
As mentioned above, phosphoric acid has 3 pKa values, and after 3 ionization it gives 3 types of ions at different pKa values:
H₃PO₄(aq)
+ H₂O(l) ⇌ H₃O⁺(aq) + H₂PO₄⁻ (aq) pKₐ₁
<span>
</span>H₂PO₄⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HPO₄²⁻ (aq) pKₐ₂
HPO₄²⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + PO₄³⁻ (aq) pKₐ₃
At the highest pKa value (12.4) of phosphoric acid, the last OH group will lose its hydrogen. On the picture I attached, it is shown required protonated form of phosphoric acid before reaction whose pKa value is 12.4.