Answer:
13 and 16
Step-by-step explanation:
let the 2 parts be x and y, then
x + y = 29 → (1) and
x² + y² = 425 → (2)
From (1) → x = 29 - y → (3)
substitute x = 29 - y into (2)
(29 - y)² + y² = 425 ( expand factor )
841 - 58y + y² + y² = 425 ( rearrange into standard form )
2y² - 58y + 416 = 0 ← in standard quadratic form
divide all terms by 2
y² - 29y + 208 = 0
Consider the factors of 208 which sum to - 29
These are - 13 and - 16, hence
(y - 13)(y - 16) = 0
equate each factor to zero and solve for y
y - 13 = 0 ⇒ y = 13
y - 16 = 0 ⇒ y = 16
substitute these values into (3)
x = 29 - 13 = 16 and x = 29 - 16 = 13
The 2 parts are 13 and 16
Answer:
-3
Step-by-step explanation:
We want (n/p)(1). We can obtain this by finding n(1) and p(1) and then dividing as indicated:
p(1) = 3(1) - 2 = 1
n(1) = 2(1) - 5 = -3
Then (n/p) (1) = -3/1, or just -3
Answer:
3x²-29x+4
Step-by-step explanation:
3x²-x-4=-30x
0=-30x-3x²+x+4
0=-3x²-29x+4
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