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3 years ago

PLZZ HELP WILL GIVE BRAINLIEST

Mathematics

2 answers:

astraxan [27]3 years ago

6 0

Answer:

(2,4)

Step-by-step explanation:

substitute the $y = 2x$ for the $y$ in $x = -y + 6$

$x = -(2x) + 6$

$x = -2x + 6$

$3x = 6$

$x = 2$

next take $x = 2$ and input it into $y = 2x$

$y = 2(2)$

$y = 4$

so if $x =2$ and $y = 4$ , the ordered pair solution is:

$(2,4)$

snow_tiger [21]3 years ago

5 0

Answer:

x=2 y=4

Step-by-step explanation:

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A square has a side that is (x-3) units long. If the area of the square is 126.5625 sq units, what is the value of x?

Kitty [74]

Answer:

14.25 units

Step-by-step explanation:

Area of a square= $l*b= (x-3)(x-3)=x^{2}-3x-3x+9=x^{2}-6x+9$

$x^{2}-6x+9=126.5625$

$x^{2}-6x-117.5625$

Solving the equation using quadratic equation then as attached

x=14.25 units

To prove

x-3=14.25-3= 11.25 units

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3 years ago

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avanturin [10]

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3 years ago

Please help! Thanks in advance.

alukav5142 [94]

In this problem, we need to plug in the given x values for $f(x)=0$ and find a and b.

When we plug in 1, we get: $2 \times {1}^{4} - 5 \times {1}^{3} - 14 \times {1}^{2} + a \times 1 + b = 0$

Simplify:
$2 - 5 - 14 + a + b = 0$
$- 17 + a + b = 0$
$a + b = 17$

We got our first statement about the values of the variables. If we find one more we can find those 2 variables.

We have another given root: 4.

Plug it in:
$2 \times {4}^{4} - 5 \times {4}^{3} - 14 \times {4}^{2} + a \times 4 + b = 0$
$512 - 320 - 224 + 4a + b = 0$
$- 32 + 4a + b = 0$
$4a + b = 32$

Now we have our second one. We can combine them:
$a + b = 17 \\ 4a + b = 32$

I use elimination method which is easier here.

Multiply the top equation by -1: $- a - b = - 17 \\ 4a + b = 32$

Add them up:
$3a = 15$

Simplify:
$a = 5$

Now we have a, we can plug in one of those equations to find b:
$5 + b = 17$
$b = 17 - 5$
$b = 12$

So, the answers are $a=5$ and $b=12$ .