Question

You begin sliding down a 15° ski slope. Ignoring friction and air resistance, how fast will you be moving after 10 s? Please express your answer in meters per second (m/s). Thank you in advance!

Answer 1

Answer:

25.4 m/s.

Explanation:

0+2.54×10=25.4m/s

Answer 2

Taking the x-coordinate to be parallel, and moving down the ramp or in other words, moving to the right will be somewhat positive.

Solution:

$E~fx=mg~sin~theta\\= sin~theta\\= a$

So...

$a = g~sin(15)\\= 2.54~m/s^2$

Use the formula [ fv = iv + at ] when iv = 0, a = 2.54, and t = 10

$fv=0+(2.54)(10)\\fv=(2.54)(10)\\fv=25.4~m/s$

Therefore, the answer is 25.4m/s

Best of Luck!