4. hyperdermis is not a layer of skin
The pairs of triangles that can be proven congruent by the hl theorem is the right angled triangle.
<h3>What is mearnt be the HL theorm?</h3>
The HL theorem is also known as the Hypothenus Leg theorem, it states that "the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent."
Learn more about the postulates of the HL theorem here:
brainly.com/question/25922842
Answer:
1.758820×10^11(-2.5i-0.8j) m/s^2
Explanation:
From the question, the parameters given are; E=(2.80i+ 5.20j) v/m, a uniform magnetic field,B= 0.400K T, acceleration, a= ??? and velocity vector, v= 11.0i metre per seconds (m/s)...
We can solve this problem using the formula below;
Ma= q[E+V × B] ---------------(1).
Note: q is negative, m= mass of electron.
Making acceleration,a the subject of the formula and substituting the parameters into equation (1);
a= -e/m × (2.5i + 5.2j +11.0i × 0.400K)
a= -e/m × (2.5i+5.2j-4.4j)
a= e/m × (-2.5i - 0.8j)
e/m= 1.758820×10^11 c/kg
Therefore, slotting in the value of charge to mass(e/m) ratio;
a= 1.7588×10^11×(-2.5i-0.8j) m/s^2
Answer:
B. It is directly proportional to the source charge.
Explanation:
Gauss's law states that the total (net) flux of an electric field at points on a closed surface is directly proportional to the electric charge enclosed by that surface.
This ultimately implies that, Gauss's law relates the electric field at points on a closed surface to the net charge enclosed by that surface.
This electromagnetism law was formulated in 1835 by famous scientists known as Carl Friedrich Gauss.
Mathematically, Gauss's law is given by this formula;
ϕ = (Q/ϵ0)
Where;
ϕ is the electric flux.
Q represents the total charge in an enclosed surface.
ε0 is the electric constant.
Hence, the statement which is true of the electric field at a distance from the source charge is that it is directly proportional to the source charge.
Answer:
The other angle is 120°.
Explanation:
Given that,
Angle = 60
Speed = 5.0
We need to calculate the range
Using formula of range
...(I)
The range for the other angle is
....(II)
Here, distance and speed are same
On comparing both range
Hence, The other angle is 120°
