For the magnetic field at some random angle to the plane of the small coil, draw a picture showing only the small coil, a vector
giving the direction of the magnetic field, the area vector for the coil, and the angle between the magnetic field and the area vector. Write an equation for the magnetic flux through the small coil at an instant of time when the area vector is at some angle to the magnetic field. Write an expression that shows how the magnetic flux through the small coil changes as it turns with a constant angular speed.
1 answer:
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Answer:
The answer is
<h2>7,840,000 J</h2>Explanation:
The kinetic energy KE of an object given it's mass and velocity can be found by using the formula
where
m is the mass
v is the velocity
From the question
m = 20000kg
v = 28 m/s
It's kinetic energy is
We have the final answer as
<h3>7,840,000 J</h3>Hope this helps you
Answer:
10581.59 V
Explanation:
We are given that
Magnetic field=B=0.65 T
Speed of electron=
Charge on electron,
Mass of electron,
We have to find the potential difference in volts required in the first part of the experiment to accelerate electrons.
Where V=Potential difference
Mass of electron
v=Velocity of electron
Using the formula
Hence, the potential difference=10581.59 V