Formula for potential energy is V=mgh, where m is mass in KG, g is earth acceleration (10 m/s^2), and h its height in meters. We know mass, acceleration is constant and also known, we know height also. Lets substitute
V=75*10*300=225000[J]=225[kJ] - its the answer
Answer:
695800 N/m^2 or Pa
Explanation:
Height of the water from the ground H = 71 m
Acceleration due to gravity g =9.8 m/s^2
density of water ρ= 1000 kg/m^3
The minimum output gauge pressure to make water reach height H
P= ρgH
= 1000×9.8×71= 695800 N/m^2 or Pa
The answer is D. 32 m.
The simple equation that connects speed (v), time (t), and distance (d) can be expressed as:
⇒
It is given:
t = 10 s
d = ?
So:
Answer:
0.4
Explanation:
Because 3m/s is the initial velocity(u) and 5m/s is the final velocity(v) and time is 5 sec.
So, acceleration = v-u ÷ t
I'm confused
