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Bas_tet [7]
2 years ago
9

I need help! Please help Me!

Physics
1 answer:
vladimir2022 [97]2 years ago
5 0

Answer:

answer is DE I hope it will help you please follow me

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Indicate whether a change in the value of each of the following determinants of demand leads to a movement along the demand curv
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Change in market price is m<span>ovement along the demand curve. </span>

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3 years ago
Which is the absolute location of St. Louis, Missouri?
devlian [24]

Answer:

The first is the closest in absolute values.

The second two are vague and the last is approximate.

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3 years ago
A rubber ball is dropped and bounces vertically from a horizontal concrete floor. If the ball has a speed of 3 m/s just before s
Ganezh [65]

Answer:

F=12.5N

Explanation:

Net force = rate of change of momentum

F = m*a

so find the change of momentum P

Pdown

P=m*v_1=0.42kg*3m/s

Pup

P=m*v_1=0.42kg*6.5m/s

dP = change in P

dP= 0.42kg (3- -.6.5)m/s =3.99 kg m/s

dT = 0.32 s

so

F = \frac{dP}{dt}=\frac{3.99Kg*m/s}{0.32s} =12.468 N

6 0
3 years ago
Ammonia is a covalent compound used in many cleaners. What is its chemical formula? N2O H2O NH3 HO3
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NH3 is the correct chemical formula
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A piece of iron of mass 200g and tempreture 300°C is dropped into 1.00 kg of water of tempreture 20°C. Predict the final equilib
Alekssandra [29.7K]

Answer:

The final equilibrium T_{f} = 25.7[°C]

Explanation:

In order to solve this problem we must have a clear concept of heat transfer. Heat transfer is defined as the transmission of heat from one body that is at a higher temperature to another at a lower temperature.

That is to say for this case the heat is transferred from the iron to the water, the temperature of the water will increase, while the temperature of the iron will decrease. At the end of the process a thermal balance is found, i.e. the temperature of iron and water will be equal.

The temperature of thermal equilibrium will be T_f.

The heat absorbed by water will be equal to the heat rejected by Iron.

Q_{iron} = Q_{water}

Heat transfer can be found by means of the following equation.

Q_{iron}=m*C_{piron}*(T_{i}-T_{f})

where:

Qiron = Iron heat transfer [kJ]

m = iron mass = 200 [g] = 0.2 [kg]

T_i = Initial temperature of the iron = 300 [°C]

T_f = final temperature [°C]

Q_{water}=m*C_{pwater}*(T_{f}-T_{iwater})

Cp_iron = 437 [J/kg*°C]

Cp_water = 4200 [J/kg*°C]

0.2*437*(300-T_{f})=1*4200*(T_{f}-20)\\26220-87.4*T_{f}=4200*T_{f}-84000\\26220+84000=4200*T_{f}+87.4*T_{f}\\110220 = 4287.4*T_{f}\\T_{f}=25.7[C]

4 0
3 years ago
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