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Veseljchak [2.6K]
3 years ago
13

The current and the potential difference in an inductor are in phase. B. The current lags the potential difference by π/2 in an

inductor C. The current leads the potential difference by π/2 in an inductor. D. none of the above
Physics
1 answer:
slava [35]3 years ago
6 0

Answer:

The current lags the potential difference by π/2 in an inductor

Explanation:

The potential difference leads to the current by  \frac{\pi}{2}. Alternate signals such as current and voltage -in this case- are periodic, this means that this signals are repeated at fixed spaces of time. Thus, In an inductor the current lags the potential difference by \frac{\pi}{2}.

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I need this type out answer question.
AveGali [126]

Answer:

<em>The ball has 7.35 joules of energy at position B.</em>

<em>The velocity of the ball at position A is 3.13 meter/second</em>

Explanation:

<u>Kinetic and Gravitational Potential Energy</u>

Kinetic energy is the form of energy that an object or a particle has by reason of its motion. An object of mass m and speed v has kinetic energy calculated by:

\displaystyle K=\frac{1}{2}m.v^2

Gravitational Potential Energy is the form of energy that an object has by reason of its height h relative to a certain reference. It can be calculated as follows:

U=m.g.h

Where g is the acceleration of gravity.

The figure shows a pendulum with a bob (ball) of mass m=1.5 Kg. When it's pulled to point B, it has a height of h= 0.5 m and set to rest.

The potential energy at that point is:

U=1.5\ Kg\cdot 9.8 \ m/s^2\cdot 0.5\ m

U=7.35\ J

The ball has 7.35 joules of energy at position B.

When the ball is released, all of the potential energy is transformed into kinetic energy when reaches point A. Thus:

K=7.35 J

From the equation of kinetic energy, we solve for v:

\displaystyle v=\sqrt{\frac{2K}{m}}

\displaystyle v=\sqrt{\frac{2\cdot 7.35}{1.5}}

\displaystyle v=\sqrt{\frac{14.7}{1.5}}

\displaystyle v=\sqrt{9.8}

v = 3.13 m/s

The velocity of the ball at position A is 3.13 meter/second

8 0
3 years ago
Describe what it means to view something from a frame of reference. Give an example to illustrate your explanation.
Komok [63]

Answer:

In physics, the concept of a frame of reference is used to specify the perspective from which an object or event is observed.

A frame of reference is where the measurements or observations will be made. Because of this, observing an event may be different when changing from one frame of reference to another, because the measurements will be different.

Defining frames of reference is necessary because the movement is relative, it may be that from our perspective or from a frame of reference on earth we are at rest, but seen from a frame of reference in space, we are in motion due that the earth is always moving.

Another example of frames of reference is a moving plane. Seen from the ground an object in the plane moves at the speed at which the plane travels, but if the frame of reference is fixed on the plane, the object is at rest.

3 0
3 years ago
If a dog is accelerating at a constant rate of 6.57 m/s2, what is the mass of the dog if 25 N of force is being applied to it?
Oliga [24]

Answer:

<h3>The answer is 3.81 kg</h3>

Explanation:

The mass of the dog can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{25}{6.57}  \\  = 3.80517503

We have the final answer as

<h3>3.81 kg</h3>

Hope this helps you

8 0
3 years ago
Once again we have a skier on an inclined plane. The skier has mass M and starts from rest. Her speed at the bottom of the slope
mars1129 [50]

Answer:

v = 31.3 m / s

Explanation:

The law of the conservation of stable energy that if there are no frictional forces mechanical energy is conserved throughout the point.

Let's look for mechanical energy at two points, the highest where the body is at rest and the lowest where at the bottom of the plane

Highest point

       Em₀ = U = m g y

Lowest point

     Em_{f} = K = ½ m v²

As there is no friction, mechanical energy is conserved

       Em₀ = Em_{f}

       m g y = ½ m v²

       v = √ 2 g y

Where we can use trigonometry to find and

       sin 30 = y / L

       y = L sin 30

Let's replace

      v = RA (2 g L sin 30)

Let's calculate

      v = RA (2 9.8 100.0 sin30)

      v = 31.3 m / s

4 0
3 years ago
A spaceship is headed toward Alpha Centauri at 0.999c. According to us, the distance to Alpha Centauri is about 4 light-years. H
aniked [119]

Answer:

According to the travellers, Alpha Centauri is <em>c) very slightly less than 4 light-years</em>

<em></em>

Explanation:

For a stationary observer, Alpha Centauri is 4 light-years away but for an observer who is travelling close to the speed of light, Alpha Centauri is <em>very slightly less than 4 light-years. </em>The following expression explains why:

v = d / t

where

  • v is the speed of the spaceship
  • d is the distance
  • t is the time

Therefore,

d = v × t

d = (0.999 c)(4 light-years)

d = 3.996  light-years

This distance is<em> very slightly less than 4 light-years. </em>

4 0
3 years ago
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