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kow [346]
3 years ago
7

Na3PO4+_CaCl2-->_NaCl + __Ca3(PO4)2​. NEED HELP ASAP

Chemistry
1 answer:
Snowcat [4.5K]3 years ago
3 0

Answer:

2Na3PO4 + 3CaCl2 → 6NaCl + Ca3(PO4)2

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How many moles of copper would be needed<br> to make 1 mole of Cu,O?
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Answer:

You can view more details on each measurement unit: molecular weight of Copper(I) Oxide or grams The molecular formula for Copper(I) Oxide is Cu2O. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Copper(I) Oxide, or 143.0914 grams.

Explanation:

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The equilibrium constant for the reaction is 1.1 x 106 M. HONO(aq) + CN-(aq) ⇋ HCN(aq) + ONO-(aq) This value indicates that
kakasveta [241]

The given question is incomplete. The complete question is given here :

The equilibrium constant for the reaction is 1.1\times 10^6 M.

HONO(aq)+CN^- (aq)\rightleftharpoons HCN(aq)+ONO^-(aq)

This value indicates that

A. CN^- is a stronger base than ONO^-

B. HCN is a stronger acid than HONO

C. The conjugate base of HONO is ONO^-

D. The conjugate acid of CN- is HCN

Answer: A. CN^- is a stronger base than ONO^-

Explanation:

Equilibrium constant is the ratio of product of the concentration of products to the product of concentration of reactants.

When K_{p}>1; the reaction is product favoured.

When K_{p}; ; the reaction is reactant favored.

When K_{p}=1; the reaction is in equilibrium.

As, K_p>>1, the reaction will be product favoured and as it is a acid base reaction where HONO acts as acid by donating H^+ ions and CN^- acts as base by accepting H^+

Thus HONO is a strong acid thus ONO^- will be a weak conjugate base and CN^- is a strong base which has weak HCN conjugate acid.

Thus the high value of K indicates that CN^- is a stronger base than ONO^-

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II<br> 5. C2H6<br> In Lewis dot structure
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H H
I I
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The complete balanced equation for the reaction between zinc hydroxide and<br> acetic acid is
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Answer:

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Explanation:

Zn(OH)2 + 2CH3COOH -----> Zn(CH3COO)2 + 2H2O

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