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solong [7]
3 years ago
14

How many moles of CuO would be required to produce 12 mol of copper metal in this reaction? CuO(s) + H2(g) —— Cu(s) + H2O(g)

Chemistry
1 answer:
Rudiy273 years ago
6 0
<h3>Answer:</h3>

12 moles

<h3>Explanation:</h3>

The equation for the reaction;

  CuO(s) + H₂(g) → Cu(s) + H₂O(g)

We are given;

  • Moles of copper, Cu is 12 moles

We are required to calculate the number of moles of CuO required;

  • From the reaction 1 mole of CuO reacts to produce 1 mole of copper
  • Thus, the mole ratio of CuO to Cu is 1 : 1
  • Moles of CuO = Moles of Cu

Thus, moles of CuO = 12 moles

Therefore; 12 moles of CuO will be required.

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CO2 + 2 NaOH → Na2CO3 + H2O
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2 years ago
Researchers used a combustion method to analyze a compound used as an antiknock additive in gasoline. A 9.394 mg sample of the c
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Answer:

The percent composition of the compound is 90.5 % C and 9.5 % H

Explanation:

Step 1: Data given

Mass of compound = 9.394 mg

Mass  of CO2 yielded = 31.154 mg

Mass of H2O yielded = 7.977 mg

Molar mass of CO2 = 44.01 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: Calculate moles CO2

moles of CO2 = (0.031154 g / 44.01 g/mol) = 7.08 * 10^-4 mol CO2

Step 3: Calculate moles C

moles of C = moles of CO2 * (1 mol C / 1 mol CO2)

moles of C = 7.08 * 10^-4 mol

Step 4: Calculate moles H2O

moles of H2O = (0.007977 g / 18.02 g/mol) = 4.43 * 10^-4 mol H2O

Step 5: Calculate moles of H

moles of H = moles of H2O * (2 mol H / 1 mol H2O)

moles of H =  4.43* 10^-4 *2 = 8.86 * 10^-4 mol H

Step 6: Calculate mass of C

mass C = moles C * molar mass C

mass C = 7.08 * 10^-4 mol*12.01 g/mol

mass C = 0.0085 grams

Step 7: Calculate mass of H

mass H = moles H * molar mass H

mass H = 8.86 * 10^-4 mol*1.01 g/mol

mass H = 0.000894 grams

Step 8: Calculate total mass of compound =

0.0085 grams + 0.000894 grams = 0.009394 grams = 9.394 mg

Step 9: Calculate the percent composition:  

% C = (8.50 mg / 9.394 mg) x 100 = 90.5%  

% H = (0.894 mg / 9.394 mg) x 100 = 9.5%

The percent composition of the compound is 90.5 % C and 9.5 % H

6 0
3 years ago
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