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3 years ago

Find the difference of -24 and -8

Mathematics

2 answers:

kramer3 years ago

6 0

The difference is -16

-24--8=16

algol [13]3 years ago

5 0

I believe the difference is -16

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Which number is irrational? A) 0.14¯¯¯¯ B) 6√ C) 13 D) 4√

nataly862011 [7]

B is correct.
because this number is around :
2.449489
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8 0

3 years ago

35. In a simple random sample of 25 high school students, the sample mean of the SAT scores was 1450, and the sample variance wa

Tatiana [17]

Answer:

$1450-2.0\frac{30}{\sqrt{25}}=1450-12$

$1450+2.0\frac{30}{\sqrt{25}}=1450+12$

And the best option would be:

c. 1450 +/- 12

Step-by-step explanation:

Information provided

$\bar X=1450$ represent the sample mean for the SAT scores

$\mu$ population mean (variable of interest)

$s^2 = 900$ represent the sample variance given

n=25 represent the sample size

Solution

The confidence interval for the true mean is given by :

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The sample deviation would be $s=\sqrt{900}= 30$

The degrees of freedom are given by:

$df=n-1=2-25=24$

The Confidence is 0.954 or 95.4%, the value of $\alpha=0.046$ and $\alpha/2 =0.023$ , assuming that we can use the normal distribution in order to find the quantile the critical value would be $z_{\alpha/2} \approx 2.0$

The confidence interval would be

$1450-2.0\frac{30}{\sqrt{25}}=1450-12$

$1450+2.0\frac{30}{\sqrt{25}}=1450+12$

And the best option would be:

c. 1450 +/- 12

3 0

3 years ago

WHOEVER GETS RIGHT GETS BRAINLIEST!!

ozzi

Answer:

Answer B: min. value at -6

Step-by-step explanation:

Complete the square of f(x) = x^2 - 2x - 5.

Note: Please use " ^ " to denote exponentiation, as shown.

Start with f(x) = x^2 - 2x - 5.

Identify the coefficient of the x term: it is 2.

Take half of that and square your result: (1/2)(2) = 1, and then 1^2 = 1.

Add and subtract this 1 between the 2x term and the constant term:

f(x) = x^2 - 2x + 1 - 1 - 5

Rewrite x^2 - 2x + 1 as a perfect square:

f(x) = (x - 1)^2 - 1 - 5, or f(x) = (x - 1)^2 - 6

Compare this to the standard form

f(x) = (x - h)^2 + k

We see that h = 1 and k = -6.

The vertex is located at (h, k); here, it's located at (1, -6).

Thus, the minimum value of this function is at the vertex (1, -6).

This agrees with Answer B: min. value at -6.

3 0

3 years ago

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Alex

10
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3 years ago

I Need this ASAP .Triangle PQR is transformed to similar triangle P'Q'R'.What is the scale factor of dilation?

almond37 [142]

I think it is c, 1 over4

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3 years ago

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