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Anna71 [15]
3 years ago
11

Carbon dioxide is a molecule made up of a single carbon atom double bonded to two oxygen atoms. The electrons are shared equally

between the carbon and the two oxygen atoms. What type of bonding does carbon dioxide have?
Chemistry
2 answers:
Margarita [4]3 years ago
7 0

Answer:ordinary covalent bond.

Explanation:

This is because their is sharing of electron between carbon and oxygen

wolverine [178]3 years ago
3 0

Answer:

The type of bonding does carbon dioxide have is covalent bonding.

Explanation:

There are 2 broadly types of chemical bonds present:

1. <u>Covalent bond:</u> This bond is present when there is sharing of electrons between two elements.

2.<u> Ionic bond:</u> This type of bond is formed when there is a complete transfer of electrons from one element to another element. In this bonding one element is always a metal and another is a non-metal.

We are given that a carbon atom is double bonded to two oxygen atoms. <u>Carbon and oxygen both are non-metals and hence, the bonds between them will be purely covalent in nature. </u>

Also, the valency of the carbon atom is 4. Thus, in the given case, the carbon atom is bonded to 2 oxygen atoms via double bonds. Thus, they all complete their octet by sharing the electrons.

<u>Hence, the type of bonding does carbon dioxide have is covalent bonding.</u>

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Stored mechanical energy is energy stored and awaiting to be used and mechanical energy is the energy that was stored being used.

6 0
3 years ago
Tin has ten stable isotopes. The heaviest, 124Sn, makes up 5.80% of naturally occuring tin atoms. How many atoms of 124Sn are pr
matrenka [14]

The average atomic mass of Sn is 118.71 g/mol

the percentage of heaviest Sn is 5.80%

the given mass of Sn is 82g

The total  moles of Sn will be = mass / atomic mass = 82/118.71=0.691

Total atoms of Sn in 82g = 6.023X10^{23}X0.691=4.16X10^{23}

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So the total atoms of Sn^{124} = 5.80% X 4.16X10^{23}

Total atoms of Sn^{124}=2.41X10^{22} atoms

the mass of Sn^{124} will be = \frac{2.41X10^{22}X124}{6.023X10^{23}}=4.96g

5 0
3 years ago
Given the following equation: 2K + Cl2 -&gt; 2KCl How many grams of KCl is produced from 4.00 g of K and excess Cl2?
Thepotemich [5.8K]

Answer:

42.65g

Explanation:

Given parameters:

Mass of K = 4g

Unknown: Mass of KCl

Solution:

  Complete equation of the reaction:

              2K + Cl₂ → 2KCl

To solve this problem, we know that the reactant in short supply is potassium K and this dictates the amount of products that would be formed. The chlorine gas is in excess and we can't use it to determine the amount of product that would form.

Now, we work from the known to the unknown. Since we know the mass of K given in the reaction, we can simply find the molar relationship between the reacting potassium and the product. We simply convert the mass to mole and compare to the product. From there we can find the mass of KCl that would be produced.

Calculating number of moles of K

      Number of moles = \frac{mass}{molar mass}

        Number of moles of K =  \frac{4}{39} = 0.103mol

From the given reaction equation:

   2 moles of K will produce 2 moles of KCl

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To find the mass of KCl produced,

   Mass of KCl = number of moles of KCl x molar mass

Molar mass of KCl = 39 + 35.5 = 74.5gmol⁻¹

Mass of KCl = 0.103 x 74.5 = 42.65g

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