Answer:
Mass of sodium metal is 130.87 gram
Explanation:
The complete reaction is
2 NaN3 --> 2 Na + 3 N2
We know that PV = nRT
n =
On substituting the given values, we get
moles of N2
Sodium azide's molar mass
3.02 *(2/3) = 2.013 moles
Mass = 2.03 * 65.01 = 130.87 gram
V2~0.4839M
We're going to use Boyles law to answer the question.
Boyle's law:
P1V1=P2V2
P1=151mmHg
P2=166mmHg
V1=0.532L
V2=?
V2=(P1 x V1)/P2
V2=(151 x 0.532)/166
Hope it helps:)
A