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Lyrx [107]
3 years ago
14

Is a instant cold pack Endothermic or Exothermic reaction? Explain.

Chemistry
1 answer:
marshall27 [118]3 years ago
3 0

Answer:

Yes an instant cold pack is a perfect example of an endothermic reaction.

Explanation:

They are endothermic because they absorb heat energy from their surroundings. This means that the surroundings of endothermic reactions are colder as a result of the reaction.For example melting ice is a type of this reaction

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How many grams of sodium make up 4.01×10^25 atoms
alexgriva [62]

Answer:

  • 5.74 ×10 25

Explanation:

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3 years ago
Low-density polyethylene is formed because _______ polymerization is very unpredictable and difficult to control.
Harlamova29_29 [7]

Answer:

radical-initiated

Explanation:

Radical-initiated polymerization is unpredictable and difficult to control. The reaction proceeds indiscriminately and produces shortened chains, loops, and branches that create holes in the polymer. This reduces its mass to volume ratio.

7 0
3 years ago
How many liters of oxygen are required to completely react with 2.0 liters of CH4 at30 °C and 3.0 atm?CH4(g) + 2O2(g) → CO2(g) +
Dominik [7]

1) Write the chemical equation.

CH_4+2O_2\rightarrow CO_2+2H_2O

2) List the known and unknown quantities.

Sample: CH4.

Volume: 2.0 L.

Temperature: 30 ºC = 303.15 K.

Pressure: 3.0 atm.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

Moles: <em>unknown</em>.

3) Moles of CH4.

<em>3.1- Set the equation.</em>

PV=nRT

<em>3.2- Plug in the known values and solve for n (moles).</em>

(3.0\text{ }atm)(2.0\text{ }L)=n*(0.082057\text{ }L*atm*K^{-1}mol^{-1})(303.15\text{ }K)n=\frac{(3.0\text{ }atm)(2.0\text{ }L)}{(0.082057\text{ }L*atm*K^{-1}*mol^{-1})}=n=0.24\text{ }mol\text{ }CH_4

4) Moles of oxygen that reacted.

The molar ratio between CH4 and O2 is 1 mol CH4: 2 mol O2.

mol\text{ }O_2=0.24\text{ }CH_4*\frac{2\text{ }mol\text{ }O_2}{1\text{ }mol\text{ }CH_4}=0.48\text{ }mol\text{ }O_2

5) Volume of oxygen required.

Sample: O2.

Moles: 0.48 mol.

Temperature: 30 ºC = 303.15 K.

Pressure: 3.0 atm.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

Volume: <em>unknown</em>.

<em>5.1- Set the equation.</em>

PV=nRT

<em>5.2- Plug in the known values and solve for V (liters).</em>

(3.0\text{ }atm)(V)=0.48\text{ }O_2*(0.082057\text{ }L*atm*K^{-1}mol^{-1})(303.15\text{ }K)V=\frac{(0.48\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(303.15\text{ }K)}{3.0\text{ }atm}V=3.98\text{ }L

3.98 L of O2<em> is required to react with 2.0 L CH4.</em>

.

6 0
1 year ago
Mencionar 5 objetos o sustancias químicas que tengan Carbono.
RoseWind [281]

Answer:    

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ropa

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Explanation:

6 0
3 years ago
In a resonant hybrid of a molecule like CH3CO2-, how are the electron orbitals of the carbon in CO2 sp hybridized?
Burka [1]
<span>The carbon  sp2 is hybridized  in any cabozxylic acid oninon and it forms one simga bond with each oxygine and one sigma bond with carbon backbone.</span>
7 0
3 years ago
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