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2 years ago

How many grams of nicotine (C10H14N2) are in a 0.125 mol sample of nicotine?

1 answer:

Ivan2 years ago

5 0

Taking into account the molar mass of the compound, 20.25 grams of nicotine (C₁₀H₁₄N₂) are in a 0.125 mol sample of nicotine.

In first place, you have to know that molar mass is a physical property that is defined as the mass of a mole of a substance, which can be an element or a compound.

In a compound the molar mass is equal to the sum of the weight or atomic mass of its atoms multiplied by the quantity of each atom.

In the periodic table, it is possible to find the molar mass of the elements, also called atomic mass or atomic weight.

The molar mass of the elements, in this case, are:

C= 12 g/mole
H= 1 g/mole
N= 14 g/mole

So, the molar mass of the compound is:

C₁₀H₁₄N₂= 10× (12 g/mole) + 14× (1 g/mole) + 2× (14 g/mole)

C₁₀H₁₄N₂= 162 g/mole

Then you can apply the following rule of three: if 1 mole of nicotine contains 162 g of the compound, 0.125 moles contains how much mass?

$mass=\frac{0.125 molesx162 grams}{1 mole}$

Solving:

mass= 20.25 grams

In summary, 20.25 grams of nicotine (C₁₀H₁₄N₂) are in a 0.125 mol sample of nicotine.

Learn more about molar mass:

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2 years ago

LICUICY NICULUM

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Answer:

Missing component

Cl₂

H₂O

Explanation:

Reaction given:

? + 2NaBr → 2NaCl+Br

Mg+? → MgO+H2

missing component = ?

Solution:

Reaction 1

? + 2NaBr -----→ 2NaCl + Br

if we look at the reactants and products there is one element is in product side but not shown in the reactant side.

In products there are following atoms

Na (Sodium)

Cl (Chlorine)

Br (Bromine)

In Reactant there are following atoms

Na (Sodium)

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if we put chlorine in the reactant then this reaction will be complete

Cl + 2 NaBr -----→ 2NaCl + Br

So chlorine react with water and give sodium chloride and bromine molecule, this is a single displacement reaction and chlorine replace bromine in the above reaction

Now balance the equation

Cl₂ + 2 NaBr -----→ 2NaCl + Br₂

So, the missing component is

Cl₂

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Reaction 2

Mg + ? ---------→ MgO + H₂

if we look at the reactants and products there are two element in product side but not shown in the reactant side.

In products there are following atoms

Mg (Magnesium)

O (Oxygen)

H (Hydrogen)

In Reactant there is only one following atom

Mg (Magnesium)

So Oxygen and Hydrogen is missing in the reactant side.

if we put water molecule (H₂O) in the reactant then this reaction will be complete

Mg + H₂O ---------→ MgO + H₂

in this reaction magnesium (Mg) react with water (H₂O) and give magnesium oxide and hydrogen gas.

So, the missing component is

H₂O

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3 years ago

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Answer:

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