How many grams of nicotine (C10H14N2) are in a 0.125 mol sample of nicotine?
1 answer:
Taking into account the molar mass of the compound, 20.25 grams of nicotine (C₁₀H₁₄N₂) are in a 0.125 mol sample of nicotine.
In first place, you have to know that molar mass is a physical property that is defined as the mass of a mole of a substance, which can be an element or a compound.
In a compound the molar mass is equal to the sum of the weight or atomic mass of its atoms multiplied by the quantity of each atom.
In the periodic table, it is possible to find the molar mass of the elements, also called atomic mass or atomic weight.
The molar mass of the elements, in this case, are:
- C= 12 g/mole
- H= 1 g/mole
- N= 14 g/mole
So, the molar mass of the compound is:
C₁₀H₁₄N₂= 10× (12 g/mole) + 14× (1 g/mole) + 2× (14 g/mole)
<u><em>C₁₀H₁₄N₂= 162 g/mole</em></u>
Then you can apply the following rule of three: if 1 mole of nicotine contains 162 g of the compound, 0.125 moles contains how much mass?
Solving:
mass= 20.25 grams
In summary, 20.25 grams of nicotine (C₁₀H₁₄N₂) are in a 0.125 mol sample of nicotine.
Learn more about molar mass:
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Hello!
If a sample contains 21.2 g N, how many moles of N does it contain?
0.66 mol
1.51 mol
14.01 mol
297.01 mol
We have the following data:
m (mass) = 21.2 g
MM (Molar mass of Nitrogen) = 14 g / mol
n (number of moles) = ?
Formula:
Solving:
Answer:
1.51 mol
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