How many grams of nicotine (C10H14N2) are in a 0.125 mol sample of nicotine?

1 answer:

Ivan2 years ago

5 0

Taking into account the molar mass of the compound, 20.25 grams of nicotine (C₁₀H₁₄N₂) are in a 0.125 mol sample of nicotine.

In first place, you have to know that molar mass is a physical property that is defined as the mass of a mole of a substance, which can be an element or a compound.

In a compound the molar mass is equal to the sum of the weight or atomic mass of its atoms multiplied by the quantity of each atom.

In the periodic table, it is possible to find the molar mass of the elements, also called atomic mass or atomic weight.

The molar mass of the elements, in this case, are:

C= 12 g/mole
H= 1 g/mole
N= 14 g/mole

So, the molar mass of the compound is:

C₁₀H₁₄N₂= 10× (12 g/mole) + 14× (1 g/mole) + 2× (14 g/mole)

C₁₀H₁₄N₂= 162 g/mole

Then you can apply the following rule of three: if 1 mole of nicotine contains 162 g of the compound, 0.125 moles contains how much mass?

$mass=\frac{0.125 molesx162 grams}{1 mole}$

Solving:

mass= 20.25 grams

In summary, 20.25 grams of nicotine (C₁₀H₁₄N₂) are in a 0.125 mol sample of nicotine.

Learn more about molar mass:

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